Unless you're able to provide a diagram representing the problem, there's not much I can do so solve this problem.
Answer:
take these as notes ig:)
Explanation:
reaction equations to make connections between the reactants and products in reactions. ... pathway: mol of O2 → mol of H2O → grams of H2O. 3.5 mol ... 25 g KClO3 ... How many grams of hydrogen gas are produced from the reaction of 221.
Answer:
There is nothing attached to this question so I unfortunately cannot help you
Explanation:
Answer:
The answer to your question is 27 g of Al
Explanation:
Data
mass of Al = ?
moles of Al₂O₃ = 0.5
The correct formula for the product is Al₂O₃
Balanced chemical reaction
4Al + 3O₂ ⇒ 2Al₂O₃
Process
1.- Calculate the molar mass of the product
Al₂O₃ = (27 x 2) + (16 x 3)
= 54 + 48
= 102 g
2.- Convert the moles of Al₂O₃ to grams
102 g ---------------- 1 mol
x ---------------- 0.5 moles
x = (0.5 x 102) / 1
x = 51 g of Al₂O₃
3.- Use proportions to calculate the mass of Al
4(27) g of Al --------------- 2(102) g of Al₂O₃
x --------------- 51 g
x = (51 x 4(27)) / 2(102)
x = 5508 / 204
x = 27 g of Al
The molecular mass is 44.01 g/mol
