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3 years ago

1.

Chemistry

1 answer:

Dahasolnce [82]3 years ago

8 0

Answer:

22.5moles

Explanation:

using mole ratio,n(CO2)/n(o)=1/2

n(CO2)=1/2n(02)

n(CO2)=1/2×45

moles of carbon dioxide produced is 22.5moles

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How many atoms are in 9.35 moles of lithium?

Fudgin [204]

Answer:

3.45 moles Li contains 2.08 × 10 (to the power of)24 atoms .

Explanation:

The relationship between atoms and moles is:

1 mole atoms =

6.022 × 10 (to the power of)23

atoms

In order to determine how many atoms occupy a given number of moles, multiply the given moles by

6.022 × 10 (to the power of)23

atoms/mole

In the case of 3.45 moles lithium (Li):

3.45 mol Li × 6.022 × 10 (to the power of)23 atoms Li/ 1 mol Li =

2.08 × 10 (to the power of)24

atoms Li rounded to three

6 0

3 years ago

Why can a molecule contain polar bonds be non polar overall?

brilliants [131]

The overall atom is non-polar because there are two negatively charged sides instead of one positive side and one negative side.

8 0

2 years ago

How many grams of product can be produced by reacting 5.0 gram of aluminum and 22 grams of bromine? 2 Al + 3 Br2 > 2 AlBr3

Crazy boy [7]

Answer:

The mass of AlBr3 is 24.5 grams

Explanation:

Step 1: Data given

Mass of aluminium = 5.0 grams

Mass of bromine = 22.0 grams

Molar mass of aluminium = 26.98 g/mol

Molar mass of br2= 159.8 g/mol

Step 2: The balancced equation

2 Al + 3 Br2 → 2 AlBr3

Step 3: Calculate moles Al

Moles Al = mass Al / molar mass Al

Moles Al = 5.0 grams / 26.98 g/mol

Moles Al = 0.185 moles

Step 4: Calculate moles Br

Moles Br = 22.0 grams / 159.8 g/mol

Moles Br = 0.138 moles

Step 5: Calculate limiting reactant

For 2 moles Al we need 3 moles Br2 to produce 2 moles AlBr3

Br2 is the limiting reactant. It will completely be consumed (0.0313 moles)

Al is in excess. There will react 2/3*0.138 = 0.092 moles

There will remain 0.185- 0.092 = 0.093 moles Al

Step 6: Calculate moles AlBr3

For 2 moles Al we need 3 moles Br2 to produce 2 moles AlBr3

For 0.0313 moles Br2 we'll have 2/3*0.138 = 0.092 moles AlBr3

Step 7: Calculate mass AlBr3

Mass AlBr3 = moles * molar mass

Mass AlBr3 = 0.092 moles * 266.69 g/mol

Mass AlBr3 = 24.5 grams

The mass of AlBr3 is 24.5 grams

3 0

3 years ago

What is the percent composition of CuCl2?

allochka39001 [22]

CuCl2 is Dichloride Copper, or Copper II Chloride.
In this Molecule, there is 1 atom of Copper for every 2 atoms of Chlorine.
If you go to the periodic table, you'll see that copper has a mass of 63.5 amu, and the chlorine 35.45 amu.
Which mean that the mass of CuCl2 is 63.5 + 35.45*2 = 63.5 + 70.9 = 134.4 g/mol.
Then, you find the ration of the mass of each atom and multiply by 100.
Ratio of Copper: $\frac{63.5}{134.4} * 100$ and you get about 47.2%
Ration of chlorice (Cl2): $\frac{70.9}{134.4} * 100$ and you get about 52.8%.

So, the percent composition of CuCl2 is 47.2% of Copper and 52.8% of chlorine.

Hope this Helps :)

4 0

4 years ago

Read 2 more answers

Calculate the frequency if the wavelength of energy is 6.5 x 10^-7m

melamori03 [73]

The answer to the problem is
69.55

5 0

3 years ago