To determine which order of the reaction it is, first we need to calculate the rate of change of moles.
the data is as follows
time 0 40 80 120 160
moles 0.100 0.067 0.045 0.030 0.020
Q1)
for the first 40 s change of moles ;
= -d[A] / t
= - (0.067-0.100)/40s
= 8.25 x 10⁻⁴ mol/s
for the next 40 s
= -(0.045-0.067)/40
= 5.5 x 10⁻⁴ mol/s
the 40 s after that
= -(0.030-0.045)/40 s
= 3.75 x 10⁻⁴ mol/s
k - rate constant
and A is the only reactant that affects the rate of the reaction
rate = k [A]ᵇ
8.25 × 10⁻⁴ mol/s = k [0.100 mol]ᵇ ----1
5.5 x 10⁻⁴ mol/s = k [0.067 mol]ᵇ -----2
divide the 2nd equation by the 1st equation
1.5 = [1.49]ᵇ
b is almost equal to 1
Therefore this is a first order reaction
Q2)
to find out the rate constant(k), we have to first state the equation for a first order reaction.
rate = k[A]ᵇ
As A is the only reactant thats considered for the rate equation.
Since this is a first order reaction,
b = 1
therefore the reaction is
rate = k[A]
substituting the values,
8.25 x 10⁻⁴ mol/s = k [0.100 mol]
k = 8.25 x 10⁻⁴ mol/s /0.100mol
= 8.25 x 10⁻³ s⁻¹
Answer:
The Answer is gonna be behavior that is simple, untaught, and born knowing:3
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The liquid particles would have moved randomly because of the increase in thermal energy. They would move randomly and would be floating in the bottle moving randomly. The liquid would turn into gas form. Meaning that you would have water particles floating in the bottle moving randomly.
Answer:
The A option is the correct answer: Non-native disulfide bonds form after beta-mercaptoethanol is removed, so the protein cannot refold correctly
Explanation:
Beta-Mercaptoehanol is responsible to reduce the four disulfide bonds present in ARNase; Urea deals with non covalente bonds. In presence of both ARNase is denatured.
If Urea is first removed by dialysis, and later is removed Beta-Mercaptoethanol, the enzyme recovers ist activity.
If Beta-Mercaptoethanol is first removed, disulfide bonds different from native use to be formed. As a result ARNase is not an active enzyme