Valence électrons don’t define which group You are in so you can cross those choices out.
A would be incorrect because element 1 has 1 valence electron while element 2 has 2 valence electrons.
D would be correct because both elements have two valence electrons.
Also, pls don’t hate if I am wrong!
Answer:
Particles of matter possess energy called kinetic energy.
Solid cannot be compressed, but gases are highly compressible.
The Kinetic energy of molecules of gases is very large & solids the least.
On heating a sublimable liquid, the molecules break free & escape from the surface of the solid directly into vapour.
Particles of matter move more rapidly on the application of heat
Answer:
positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).
Here we have to choose the correct statement behind the polarity of the water molecule.
The polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.
The bonding of the water (H₂O) molecule is shown in the figure. There remain two lone pair of electrons on the oxygen atom. The oxygen atom has 6 valence electrons among which 2 are involved to make the covalent bond with two hydrogen atom.
The lone pair if electrons exerted lone pair-bond pair repulsion and H₂O has a bent structure as shown in the figure. In this way the dipole moment generated by oxygen and hydrogen cannot be nullified and it has a permanent dipole moment which leads the molecule to be polar in nature.
The water molecule is not linear in nature it has bent structure.
There is a huge difference of electronegativity between the hydrogen (H) and oxygen (O) atom. The oxygen atom is highly electronegative whereas the hydrogen atom is electropositive in nature.
The hydrogen bond formation is due to the fact the molecule is polar in nature.
Note: The question is incomplete. The complete question is given below :
Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0.75 cal/g°C in the liquid state. If 5.0 kcal of heat are applied to a 50 g sample of the substance at a temperature of 24°C, what will its new temperate be? What state will the sample be in? (melting point of the substance = 27°C; specific heat of the solid =0.48 cal/g°C; boiling point of the substance = 700°C)
Explanation:
1.a) Heat energy required to raise the temperature of the substance to its melting point, H = mcΔT
Mass of solid sample = 50 g; specific heat of solid = 0.75 cal/g; ΔT = 27 - 24 = 3 °C
H = 50 × 0.75 × 3 = 112.5 calories
b) Heat energy required to convert the solid to liquid at its melting point at 27°C, H = m×l, where l = 45 cal/g
H = 50 × 45 = 2250 cal
c) Total energy used so far = 112.5 cal + 2250 cal = 2362.5 calories.
Amount of energy left = 5000 - 2362.5 = 2637.5 cal
The remaining energy is used to heat the liquid
H = mcΔT
Where specific heat of the liquid, c = 0.75 cal/g/°C, H = 2637.5 cal, ΔT = temperature change
2637.5 = 50 × 0.75 x ΔT
ΔT = 2637.5 / ( 50*0.75)
ΔT = 70.3 °C
Final temperature of sample = (70.3 + 27) °C = 97.3 °C
The substance will be in liquid state at a temperature of 97.3 °C
i hope that this eg gonna help u