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vivado [14]
3 years ago
11

8 is 40% of what

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0

Answer:

20

Step-by-step explanation:

40/100 of x = 8

x = 8 x 100 / 40 = 20

( I hope im right!!)

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PLZ HELP NEED ASAP, much appreciated
Margaret [11]

Answer:

Ok that's not it

x=-1 then y=4

x=0 then y= 6

x=1 then y = 8

x=2 then y= 10

x=3 then y= 12

Step-by-step explanation:

when y=2x+6

you have to plug what it says x is in each of the equations.

For the first one it says x=-1

you then plug that in and you get y=2(-1)+6

then you go through PEMDAS and first you get y=-2+6

-2+6 = 4

therefore y=4

and you just go through the rest wiht that

Step-by-step explanation:

6 0
2 years ago
Order the group of quadratic functions from widest to narrowest graph <br> y=3^2, y=5^2, y=7^2
Sedbober [7]
Y = 7^2
y = 5^2
y = 3^2

if wide is the greatest and narrow means smallest then i hope its right

Ur Welcome and if its wrong plz let me know and i will fix it,
xXharleyquinn04Xx
7 0
3 years ago
What is the equation for a Vertical Shift 5 units up?
lys-0071 [83]
F(x) = x2 + 5

This function comes from the basic function f(x) = x2 with the constant 5 added to the outside. This gives the basic function a vertical shift UP 5 units.
7 0
3 years ago
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g100num [7]
The curved surface area is equal to about 354.53
4 0
3 years ago
PLEASE HELP
Ksivusya [100]

Answer:

Option (1)

Step-by-step explanation:

Coordinates of the vertices of a quadrilateral WXYZ drawn in the figure are,

W(-1, 4), X(2, 2), Y(0, -1), Z(-3, 1)

Length of a segment having ends as (x_1, y_1) and (x_2, y_2) is represented by,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Length of WX = \sqrt{(-1-2)^2+(4-2)^2}

                       = \sqrt{9+4}

                       = \sqrt{13}

Length of XY = \sqrt{(2-0)^2+(2+1)^2}

                      = \sqrt{13}

Length of YZ = \sqrt{(0+3)^2+(-1-1)^2}

                      = \sqrt{13}

Length of ZW = \sqrt{(-1+3)^2+(4-1)^2}

                      = \sqrt{13}

Slope of side WX (m_1) = \frac{y_2-y_1}{x_2-x_1}

                                  = \frac{4-2}{-1-2}

                                  = -\frac{2}{3}

Slope of side XY (m_2) = \frac{2+1}{2-0}

                                    = \frac{3}{2}

By the property of perpendicular lines,

m_1\times m_2=-1

(-\frac{2}{3})(\frac{3}{2})=-1

therefore, WX and XY are perpendicular.

Slope of YZ (m_3) = \frac{-1-1}{0+3}=-\frac{2}{3}

m_2\times m_3=(\frac{3}{2})\times (-\frac{2}{3})=-1

Therefore, XY ⊥ YZ

Similarly, we can prove YZ ⊥ ZW.

Therefore, quadrilateral WXYZ is a SQUARE.

Option (1) will be the answer.

7 0
3 years ago
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