Question

P is a rectangle with a length of 40cm and width of x cm

Answer 1

The ratio x:y as required in the task content is; 25:18.

What is the ratio x:y as required?

It follows from the information given in the task content that;

The area of rectangle P is; 40x.

The area of rectangle Q is; y × (1.25 × 40) = 50y.

Hence, since the area of Q is 10% less than the area of P, it follows that A(q) = 0.9A(p).

And, A(p)/A(q) = 10/9

Hence, 10/9 = 40x/50y

x/y= 50/36 = 25/18

Hence, the required ratio is; 25: 18.

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