Because the vertex of the parabola is at (16,0), its equation is of the formy = a(x-10)² + 15
The graph goes through (0,0), thereforea(0 - 10)² + 15 = 0100a = -15a = -0.15
The equation is y = f(x) = -0.15(x - 10)² + 15
The graph is shown below.
Part A
Note that y = f(x).
The x-intercepts identify values where the function or y=0. The x-intercepts occur at x=0 and x=20, or at (0,0) and (20,0).
The maximum value of y occurs at the vertex (10, 15) because the curve is down due to the negative leading coefficient of -0.15.
The curve increases in the interval x = (-∞, 10) and it decreases in the interval x = (10, ∞).
Part B
When x=12, y = -0.15(12 - 10)² + 15 = 14.4When x=15, y = -0.15(15 - 10)² + 15 = 11.25
The average rate of change between x =12 to x = 15 is(11.25 - 14.4)/(15 - 12) = -1.05
This rate of change represents the slope of the secant line from A to B. It approximates the rate at which f(x) decreases in the interval x =[12, 15].
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Answer:
#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.
#4.) Find how many minutes until the barrel is empty of water.
Let y = 0, to solve for time x.
0 = (-2/5)*x + 18
(2/5)*x = 18
x = (5/2)* 18 = 5*9 = 45 minutes
Up to and after 45 minutes, the barrel is empty of water.
Step-by-step explanation:
#2.)
minutes: 5, 10, 15, 20
water(gal): 16, 14, 12, 10
Find slope: slope m = (14 - 16)/(10 - 5) = -2/5
y - 10 = (-2/5)*(x - 20)
y - 10 = (-2/5)* x + 8
y = (-2/5)*x + 18
rate of change slope means that for every minute 2/5 gallons of water is lost
#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.
#4.) Find how many minutes until the barrel is empty of water.
Let y = 0, to solve for time x.
0 = (-2/5)*x + 18
(2/5)*x = 18
x = (5/2)* 18 = 5*9 = 45 minutes
