Help asap, please!!..

kondaur [170]

Do _____ times ______

8 0

3 years ago

At lavernes swimwear there are 6 bikini styles and 2 other types of swimsuit what percent of the swimsuit styles are bikinis?

ELEN [110]

Answer:

33.33%

Step-by-step explanation:

6 bikini styles and 2 other types

so, total types is 3

so, bikinis is only 1 of the 3, which is 1/3 or 33.33%

6 0

4 years ago

Read 2 more answers

Plot the x- and y-intercepts to graph the equation.<br> Y =<br> = 1x – 1

vlabodo [156]

Answer:

plot points (0, -1) and (3, 0)

Step-by-step explanation:

compare the given equation to

y=mx +b where b is the y-intercept

y= 1/3 x -1 so thhe y-intercept is at point (0, -1)

to find the x-intercept make y=0

x/3 -1 =0

x/3 =1

x= 3 so x-intercept is at point (3, 0)

5 0

3 years ago

Solve for x. 1.1x + 1.2x - 5.4 = -10

Andru [333]

Answer:

x ≈ - 1.83

Step-by-step explanation:

to solve for x in the question 1.1x + 1.2x - 5.4 = -10

we have

2.3x - 5.4 = -10

collect the like terms

2.3x = -10 + 5.4

2.3x = -4.2

divide both sides by the coefficient of x

2.3x/2.3 = -4.2/2.3

x = -1.826

x ≈ - 1.83

4 0

3 years ago

Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid

Gnom [1K]

Answer:

The area of the triangle is $A=\sqrt{\frac{4027}{2}}$

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

$A=\frac{1}{2}||{\bf u} \times {\bf v} ||$

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

${\bf AB}$ and ${\bf AC}$

The vector ${\bf AB}$ is the difference of point B minus point A

${\bf AB}=(5-3,5-5,0-9)=(2,0,-9)$

and the vector ${\bf AC}$ is the difference of point C minus point A

${\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)$

Next we need to find the cross product of this vectors.

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

This is the definition of cross product of two vectors in space:

Let ${\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k}$ and ${\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k}$ be vectors in space. The cross product of ${\bf u}$ and ${\bf v}$ is the vector

${\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}$

Applying this definition we get

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

$\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}$

$||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}$

The area of the triangle is

$A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}$

7 0

4 years ago