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9966 [12]
3 years ago
11

Keith, Jason, Alyssa and Monique each have 27 playing cards. How many card to they have in all?

Mathematics
1 answer:
gtnhenbr [62]3 years ago
8 0

Answer: I think its 81 but i'm not that sure.

Step-by-step explanation:

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5. Classify each triangle by its angle and sides
PIT_PIT [208]

Answer:

5 is D

6 is C

Step-by-step explanation:

Define:

Equilateral - All sides and angles are congruent

Isosceles: Two congruent sides and two congruent angles

Scalene: No congruent sides or angles

Right triangle: A triangle with a right angle ( note that a right angle has a measure of 90 degrees )

obtuse triangle: A triangle with an obtuse angle ( obtuse angles have a measure of more than 90 degrees. )

Acute triangle : A triangle with an acute angle ( an acute angle has a measure of less than 90 degrees )

Answer:

the triangle shown in # 5 has a right angle and 2 congruent sides and angles

Therefore the triangle in #5 is a right isosceles

The triangle shown in #6 has an angle with a measure that is more than 90 degrees and have no congruent sides or angles therefore the triangle in #6 is an obtuse scalene.

3 0
3 years ago
Factor completely: <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20" id="TexFormula1" title=" x^{2} " alt=" x^{2} " align="ab
Maurinko [17]
24  = 6 * 4
and 
6 + 4 = 10


so its the last choice.
6 0
3 years ago
Read 2 more answers
Given: If a child is at least 4 feet tall, then
KIM [24]

Answer:

F

Step-by-step explanation:

7 0
3 years ago
When there is no equal sign, the polynomial is called an ___________.
Tanya [424]
The answer is expression
3 0
1 year ago
How do I add and subtract radicals with no like terms
liq [111]

Most real number arithmetic is pretty vacuous

\sqrt 2 + \sqrt 3 = \sqrt{2} + \sqrt{3}

That's about as good a way as possible to write this particular real number. But it's far from the only way.

(\sqrt 2 + \sqrt 3)^2 = \sqrt{2}^2 + 2\sqrt 2 \sqrt 3 + \sqrt{3}^2 = 5 + 2 \sqrt 6

so

\sqrt 2 + \sqrt 3 = \sqrt{5 + 2 \sqrt 6}

Sometimes you can factor something out and you have a common radical:

\sqrt{32} + \sqrt{128} = \sqrt{2^5} + \sqrt{2^7} = 4 \sqrt{2} + 8 \sqrt{2} = 12 \sqrt{2}

But most of them are vacuous,

3\sqrt{7} + 34 \sqrt{13} = 3\sqrt{7} + 34 \sqrt{13}


8 0
3 years ago
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