Answer:
x = 20
Step-by-step explanation:
x° + 2x° + (x+10)° = 90°
3x° + x° + 10° = 90°
4x° + 10° = 90°
4x° = 90°-10°
4x° = 80°
x = 80/4
x = 20
36
Step-by-step explanation:
4 5/8*3 is 13.875
500 decided by 13.875 is a little over 36, so you can make 36 full ribbons
Hii!
So I did this and I have A!
A: You cannot get the mean from the graph but you CAN get the third quartile!
B: To find the interquartile range (IQR) we subtract the third and first quartiles:
60-35 = 25
C: An outlier would be much larger than the rest of the data or much smaller than the rest of the data. An outlier would make the "whisker" portion longer and could potentially slightly shift the box.
Observe attached picture.
On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft
When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.
We can apply trigonometry rules to find height of flagpole.
From small triangle containing sign we can find tangens function:

Similarly we can do for large triangle containing flagpole:

We see that these two equations have same left sides. This means that their right sides must also be same:

We can solve for A:

Height of flagpole is 48 feet.
-1/2 ans. Hope it helps..