Answer:
<em />
- <em>It takes</em><u> 2.5 minutes </u><em>to fill the tank.</em>
Explanation:
The net speed or net rate for filling the 10-liters tank is equal to the speed the tap is filling less the speed the water is leaking through the hole located at the bottom of the tank:
- Net rate = rate of filling - rate of leaking
- Net rate = 5 liters/minute - 1 liter/minute
- Net rate = 4 liters/minute
Thus, consiedering the tank is empty at the beginning, the time is:
- Time = Volume of the tank / net rate of filling
- Time = 10 liters / (4liters/minute)
- Time = 2.5 minutes ← answer
Good evening
Answer:
<em>a) the cost of one apple is €</em><em>0.9</em>
<em>b) the cost of one pineapple is €</em><em>5.4</em>
<em>c) the cost of two pineapples and six apples is €</em><em>16.2</em>
Step-by-step explanation:
Consider P the price of a pineapple
A the price of an apple
A pineapple costs six times as much as an apple means P = 6A
Mum paid €7.20 for one pineapple and two apples means P + 2A = 7.20
then
6A + 2A = 7.20
then
8A = 7.20
then
A = €0.9
Since P = 6A then P = 6×(0.9) = €5.4
the cost of two pineapples and six apples
= 2P + 6A
= 2P + P
= 3P
= 3×(5.4)
= €16.2
Answer:
3
- 48
Step-by-step explanation:
Given
(a + 2)(3a² + 12)(a - 2)
= (a + 2)(a - 2)(3a² + 12) ← expand the first pair of parenthesis using FOIL
=(a² - 4)(3a² + 12) ← expand using FOIL
= 3 + 12a² - 12a² - 48 ← collect like terms
= 3 - 48
Answer:
We want to rewrite:
q^2 = a*(p^2 - b^2)/p
as a linear equation, in the form:
y = m*x + c
So we start with:
q^2 = a*(p^2 - b^2)/p
we can expand the left side to get:
q^2 = (a/p)*p^2 - (a/p)*b^2
q^2 = a*p - (a/p)*b^2
Now we can ust define:
a*p = c
Then we can replace that to get:
q^2 = -(a/p)*b^2 + c
now we can replace:
q^2 = y
b^2 = x
Replacing these, we get:
y = -(a/p)*x + c
finally, we can replace:
-(a/p) = m
then we got the equation:
y = m*x + c
where:
y = q^2
x = b^2
c = a*p
m = -(a/p)
Answer:the pairs are not a quadratic eqation
Step-by-step explanation:
The differences between the differences of the y value are not consistent
