A recursive sequence is a sequence in which terms are defined using one or more previous terms that are given.
If you know the term n of an arithmetic sequence and you know the common difference, d, you can find the term (n + 1) by tossing the recursive formula to n + 1 = a n + d
We have then:
5, 15, 30, 50
an = (5/2) * (n) * (n + 1)
Answer:
the recursive formula for 5, 15, 30, 50, is:
an = (5/2) * (n) * (n + 1)
the first ones -35
the second one is 2
4 divided by y < 5
put aline under the less than side
Answer:
( 300; 353) is on the line y=1.2x−7
Step-by-step explanation:
y=1.2x−7
Substitute the point into the equation and see if it is true
353=1.2(300)−7
353 =360-7
353 = 353
This point is on the line
Answer:
The range of the function will be: {-9, -5, -1, 3, 7}
Step-by-step explanation:
- We also know that the range of a function is the set of values of the dependent variable for which a function is defined.
Given the function
f(x) = 2x - 1
Given that the domain of the function is:
{-4, -2, 0, 2, 4}
Putting x=-4
f(x) = 2x - 1
f(-4)= 2(-4)-1=-8-1=-9
Thus,
at x=-4, y = -9
Putting x=-2
f(x) = 2x - 1
f(-2)= 2(-2)-1=-4-1=-5
Thus,
at x=-2, y = -5
Putting x=0
f(x) = 2x - 1
f(0)= 2(0)-1=0-1=-1
Thus,
at x=-2, y = -1
Putting x=2
f(x) = 2x - 1
f(2)= 2(2)-1=4-1=3
Thus,
at x=-2, y = 3
Putting x=4
f(x) = 2x - 1
f(4)= 2(4)-1=8-1=7
Thus,
at x=-2, y = 7
We also know that the range of a function is the set of values of the dependent variable for which a function is defined.
Thus, the range of the function will have all the y values correspond to all the x values for which the function is defined.
Thus, the range of the function will be: {-9, -5, -1, 3, 7}
