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goblinko [34]
3 years ago
15

Gillian and her friends are playing a card game using a standard deck, but without the aces. In the deck, there are 36 numbered

cards, 4 jacks, 4 queens, and 4 kings. The numbered cards are worth 1 point, jacks are worth 2 points, queens are worth 3 points, and kings are worth 4 points. Each person draws one card, writes down what its worth, and then puts it back. The player with the highest point total after 10 rounds wins. If there are 4 players playing the game, what is the best prediction for the amount of numbered cards that will be drawn during the game?
Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

30

Step-by-step explanation:

To find the best prediction for the amount of numbered cards that will be drawn during the game, first find the probability of drawing a numbered card. There are 36 numbered cards and 48 total cards. So, the probability of drawing a numbered card is  or .

Now, multiply the probability by the number of times a card will be drawn from the deck. Since there are 10 rounds and 4 players, a card will be drawn from the deck 10 × 4, or 40, times. So, multiply  by 40.

Therefore, the best prediction for the amount of numbered cards that will be drawn during the game is 30.

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Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event
bekas [8.4K]

Answer:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

p(A) = \frac{5}{7}

p(B) = \frac{2}{3}

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

P(A|B) = P(A)

P(B|A) = P(B)

And for this special case we want to find this probability:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

7 0
3 years ago
Could any kind person help me with this equation please
kondor19780726 [428]

M’ (-4, 7)

N’ (0, 5)

P’ (2, 0)

Q’ (-2, 1)

you basically change the x and y values by the value it says so you'd subtract 4 from x (the first number) and add 1 to y (the second number)

5 0
3 years ago
Whats is the anwser to twelve times twenty
balandron [24]

Answer:240

Step-by-step explanation:

120

× 12

------

240

5 0
3 years ago
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snow_lady [41]

Answer:

This relation represent y as a function of x, because each value of x is associated with a single value of y

Step-by-step explanation:

we know that

A function is a relation from a set of inputs (x values) to a set of possible outputs (y values) where each input is related to exactly one output

we have the relation

(3, 4), (4, 3), (6, 3), (7, 8), (5, 4)

This relation represent y as a function of x, because each value of x is associated with a single value of y

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3 years ago
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8_murik_8 [283]

Answer:

Step-by-step explanation:

You've typed the equation incorrectly. 3^5x-1 = 3⁵x-1.

It needs to be typed as 3^(5x-1) = 7.

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