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1 year ago

Z-4/4+8= z + 9, z - 3, z - 7, z + 7

Mathematics

1 answer:

Sladkaya [172]1 year ago

7 0

The values of the expressions are -17/3, -29/3 and 13/3

<h3>How to solve the expressions?</h3>

The equation is given as:

z-4/4+8= z + 9

Rewrite properly as

$\frac{z-4}{4}+8= z + 9$

Subtract 8 from both sides

$\frac{z-4}{4}= z + 1$

Multiply through by 4

z - 4 = 4z + 4

Evaluate the like terms

3z = -8

Divide by 3

z = -8/3

Substitute z = -8/3 in z - 3, z - 7 and z + 7

z - 3 = -8/3 - 3 = -17/3

z - 7 = -8/3 - 7 = -29/3

z + 7 = -8/3 + 7 = 13/3

Hence, the values of the expressions are -17/3, -29/3 and 13/3

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Step-by-step explanation:

Trying to factor as a Difference of Squares :

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Proof : (A+B) • (A-B) =

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Equation at the end of step 1 :

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Step 2 :

Solving a Single Variable Equation :

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Add 96 to both sides of the equation :

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When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

r = ± √ 96

Can √ 96 be simplified ?

Yes! The prime factorization of 96 is

2•2•2•2•2•3

To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

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Two solutions were found :

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Processing ends successfully

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3 years ago

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3 years ago

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Step-by-step explanation:

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First we need to find

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We need to find value of x

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3 years ago

Z-​4/​4+​8= z + 9, z - 3, z - 7, z + 7

Z-4/4+8= z + 9, z - 3, z - 7, z + 7