M<FSM = m<WSU
7x+ 8 = 5x + 32
2x = 24
x = 12
m<FSM = 7x+ 8 = 7(12) + 8 = 84 + 8 = 92
answer
A 92
9514 1404 393
Explanation:
From your knowledge of the world, you know that ...
- the cost of multiple items is the sum of their individual costs
- multiplication can be used for repeated addition
- utility fees are the sum of fixed fees and usage-related fees
- for a phone plan, text message costs are a usage-related fee
The problem statement asks for the cost of a single text message. For the purpose of finding that value, it is convenient to represent it using the variable <em>t</em>. The problem statement says Eric was billed for 450 text messages, so we expect his usage-related fee to be 450t, the sum of the costs of 450 messages--using multiplication for the repeated sum.
The problem statement says Eric was billed 12.50 for fixed fees. So, we expect Eric's total bill to be ...
fixed fees + usage-related fees = 12.50 + 450t
The problem statement says Eric's total bill was 35.00, so we assume that is the sum of the above-listed fees. That is, the two ways to express Eric's total bill are equal.
12.50 +450t = 35.00
We write the equation in terms of dy/dx,
<span>y'(x)=sqrt (2y(x)+18)</span>
dy/dx = sqrt(2y + 18)
dy/dx = sqrt(2) ( sqrt(y + 9))
Separating the variables in the equation, we will have:
<span>1/sqrt(y + 9) dy= sqrt(2) dx </span>
Integrating both sides, we will obtain
<span>2sqrt(y+9) = x(sqrt(2)) + c </span>
<span>where c is a constant and can be determined by using the boundary condition given </span>
<span>y(5)=9 : x = 5, y = 9
</span><span>sqrt(9+9) = 5/sqrt(2) + C </span>
<span>C = sqrt(18) - 5/sqrt(2) = sqrt(2) / 2</span>
Substituting to the original equation,
sqrt(y+9) = x/sqrt(2) + sqrt(2) / 2
<span>sqrt(y+9) = (2x + 2) / 2sqrt(2)
</span>
Squaring both sides, we will obtain,
<span>y + 9 = ((2x+2)^2) / 8</span>
y = ((2x+2)^2) / 8 - 9
Answer:
The slope is 0.3.
Step-by-step explanation:
1.5x + 4.5y = 18
<u>4.5y</u> = <u>18 - 1.5x</u>
4.5 4.5
y = 4 - 0.3x
Answer:
6:7
Step-by-step explanation:
divide both sides by 7...
