(x - 5i√2)(x +5i√2)
given the roots of a polynomial p(x), say x = a and x = b
then the factors are (x - a)(x - b)
and p(x) is the product of the factors ⇒ p(x) = (x - a)(x - b)
here x² + 50 = 0 ⇒ x² = - 50 → ( set = 0 for roots)
take the square root of both sides
x = ± √-50 = ± √(25 × 2 × -1) = √25 × √2 × √-1 = ± 5i√2
The roots are x = ± 5i√2
thus the factors are ( x - ( - 5i√2)) and (x - (+5i√2))
x² + 50 = (x + 5i√2)(x - 5i√2)
Answer:
x = ± 2
Step-by-step explanation:
Given
12 - x² = 0 ( add x² to both sides )
12 = x² or
x² = 12 ( take the square root of both sides )
x = ±
= ± 
= ± 2
Answer:
B=D
Step-by-step explanation:
Wild guess because no context.
Answer:$3.672
rounded is $3.67
Step-by-step explanation:
Answer:
3x(2x - 3)
Step-by-step explanation:
Given
y = 6x² - 9x ← factor out 3x from each term
= 3x(2x - 3)
