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Vlad [161]
2 years ago
11

Using the following image, if E is the midpoint of FD find ED.What is ED?

Mathematics
2 answers:
klio [65]2 years ago
6 0

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: ED = 5 \:\: units

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:FE + ED = FD

\qquad \tt \rightarrow \:5 + x = 10

\qquad \tt \rightarrow \:x = 10 - 5

\qquad \tt \rightarrow \:x = 5

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

ELEN [110]2 years ago
3 0

Answer:

10-5=5

Step-by-step explanation:

FD-FE=ED

FD=10

FE=5

10-5=5

ED=5

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A stack of cards is numbered 1 to 21. Leilani pulls one card from the stack. What is the best approximation for the probability
arlik [135]

Answer:

The approximation is 0.2( real value is 0.19)

Step-by-step explanation:

In this question, we are to calculate the best approximation if in a pack of cards labeled 1 to 21 , the card selected is a multiple of 5

First we know that the total number of options in our sample space is 21; from 1 to 21

now let’s get the multiples of 5. we have 5,10,15 and 20

The probability of selecting a multiple of 5 is thus; 4/21 . This can be approximately be said to be 0.2 ( actual value is 0.19)

7 0
3 years ago
Can someone anwer this pleaseeee
AnnyKZ [126]

Answer:

D

Step-by-step explanation:

the formula of 90 Degree angle

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5 0
3 years ago
Read 2 more answers
5. Is the sequence arithmetic? If so, identify the common difference.
HACTEHA [7]
5.
aritmetic is same increase per term
14 to 21 is 7
21 to 42 is 21
7≠21
no


6.
decreases by 4 each time
an=a1+d(n-1)
an=10-4(n-1)
n=12 for 12th term
a12=10-4(12-1)
a12=10-4(11)
a12=10-44
a12=-34

it is -34



7.
missing term is y
22+n=y
y+n=34
22+n+n=34
22+2n=34
minus 22 from both sides
2n=12
divide both sides by 2
n=6
22+n=y
22+6=y
28=y

28 is answer



5. no
6. -34
7. 28
6 0
3 years ago
Read 2 more answers
Which of the following is equivalent to 2/9
iragen [17]

Answer:

B would be the answer:))

Step-by-step explanation:

Divide 2 by 9

5 0
2 years ago
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Write out each step of the 3-step test for continuity for the following functions at the given point. If the function is discont
balandron [24]

If we simply substitute the value x=2 in the expression we have

f(2) = \dfrac{4-12+8}{4-2-2} = \dfrac{0}{0}

which is undefined.

But if we factor both numerator and denominator, we have

f(x)=\dfrac{x^2-6x+8}{x^2-x-2} = \dfrac{(x-2)(x-4)}{(x+1)(x-2)}

Since we are studying the limit as x approaches 2, we can assume that x is not 2. In this case, we can simplify the (x-2) parenthesis, and the expression becomes

f(x)=\dfrac{x-4}{x+1}

And we can evaluate this at 2 with no problems:

f(2) = \dfrac{2-4}{2+1} = -\dfrac{2}{3}

So, we have

\displaystyle \lim_{x\to 2}f(x) = -\dfrac{2}{3}

This means that in this case both left and right limits exist and are the same, so the limit exists, but the function is not defined at x=2. This is a removable discontinuity, because we can define the function as its limit, and we have a continuous function at x=2:

f(x) = \begin{cases}\dfrac{x^2-6x+8}{x^2-x-2} &\text{if }x \neq 2\\ -\frac{2}{3} &\text{if }x = 2\end{cases}

8 0
4 years ago
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