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Vlad [161]
2 years ago
11

Using the following image, if E is the midpoint of FD find ED.What is ED?

Mathematics
2 answers:
klio [65]2 years ago
6 0

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: ED = 5 \:\: units

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:FE + ED = FD

\qquad \tt \rightarrow \:5 + x = 10

\qquad \tt \rightarrow \:x = 10 - 5

\qquad \tt \rightarrow \:x = 5

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

ELEN [110]2 years ago
3 0

Answer:

10-5=5

Step-by-step explanation:

FD-FE=ED

FD=10

FE=5

10-5=5

ED=5

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How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
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7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
What is the greatest possible error of 18.9?<br> What is the greatest possible error of 11 1/8 oz?
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