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mafiozo [28]
2 years ago
6

Find the zeros of f(x) = x + 7x + 9 by using the Quadratic Formula.​

Mathematics
1 answer:
REY [17]2 years ago
4 0

:))))))))))))))))))))))

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3(7x+2)+6x plz answer
Natalija [7]

Answer:

27x +6

Step-by-step explanation:

3(7x+2)+6x

Distribute

21x+6 +6x

Combine like terms

27x +6

4 0
3 years ago
Read 2 more answers
What must be true for lines a and b to be parallel lines? Check all that apply
iren [92.7K]

the question does not present the options, but this does not interfere with the resolution


we know that

if a and b are parallel lines

so


1) m∠2=58°------> by corresponding angles


2) m∠1=4x-10------> by alternate exterior angles


3) [m∠2+m∠(3x-1)]+m ∠1=180°------> by supplementary angles

58+(3x-1)+4x-10=180

7x=180-47

7x=133

x=19°


4) angle (4x-10)=-4*19-10-------> 66°


5) angle 3x-1=3*19-1-------> 56°

3 0
3 years ago
Blanca's house is assessed at $149,000 and her property tax rate is 2.3%. How much is her annual property taxes?
mrs_skeptik [129]
$3,427 because you take 149000 and multiply by .023 for 2.3%.
5 0
3 years ago
Read 2 more answers
the ratio of boys to girls at the beach cleanup was 7:8. If there were 43 boys, how many girls were there?
faltersainse [42]
I'm pretty sure there were 48 girls at the beach clean up. 43 ÷ 7 = 6.14 (6 cause there's not gonna be floating males with missing body parts). So we multiply 6 x 8 and we get 48.
7 0
3 years ago
Use implicit differentiation to find the negative slope of a tangent to the circle x^2+y^2=16 at x=-2
SVETLANKA909090 [29]

Answer:

slope = - \frac{\sqrt{3} }{3}

Step-by-step explanation:

Differentiating implicitly with respect to x

2x + 2y \frac{dy}{dx} = 0

2y \frac{dy}{dx} = - 2x

\frac{dy}{dx} = - \frac{2x}{2y} = - \frac{x}{y}

\frac{dy}{dx} is the measure of the slope of the tangent

rearrange equation to find corresponding y-coordinate of x = - 2

y² = 16 - 4 = 12 = 2\sqrt{3} ⇒ y = ± 2\sqrt{3}

using x = - 2, y = - 2\sqrt{3}, then

\frac{dy}{dx} = - \frac{1}{\sqrt{3} } = - \frac{\sqrt{3} }{3}


3 0
3 years ago
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