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2 years ago

Choose the most convenient method to graph the line y=−13x+5

Mathematics

1 answer:

lapo4ka [179]2 years ago

6 0

Answer:

X and Y intercept

Step-by-step explanation:

X and Y intercept is much easier as the equation is linear it is easy to find the intercepts

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What is the perimeter of a square with sides of 17ft

Elodia [21]

68 ft. 17 times 4 sides = perimeter.

6 0

3 years ago

Read 2 more answers

The water temperature at the beach

tester [92]

Answer: 69˚

All of the graphs for the surf breaks presented on Surf-Forecast.com are on the same scale to enable comparison between locations around the world.

Ocean Beach water temperatures peak in the range 13 to 17°C (55 to 63°F) on around the 8th of September and are at their lowest on about the 7th of April, in the range 10 to 14°C (50 to 57°F). The highest water temperatures at Ocean Beach in early to mid September are ideally suited to a 4/3mm wetsuit + 3mm boots, although a 5/3mm wetsuit may be preferable for longer sessions and cold windy days. At its lowest in the first part of April, low water temperatures at Ocean Beach are suited to a 5/4mm or 5/3mm good quality wetsuit with neoprene gloves and 3mm boots. You will need a hood if it's windy or the air is cold.

Actual sea surface water temperatures close to shore at Ocean Beach can vary by several degrees compared with these open water averages. This is especially true after heavy rain, close to river mouths or after long periods of strong offshore winds. Offshore winds cause colder deep water to replace surface water that has been warmed by the sun. Air temperature, wind-chill and sunshine should also be considered before deciding on the kind of wetsuit needed to stay warm when surfing at Ocean Beach.

Hope this. helps!~

3 0

3 years ago

Triangle X Y Z is shown. If m∠X = 34° and m∠Z = 26°, what is m∠Y?

nordsb [41]

Answer:

given, triangle XYZ in which m of angle X=34°

angle Z= 26°

now,angle Y =?

we have,

AngleX + angle Y+ angle Z = 180°

or, 34°+angle Y +26°=180°

or, angle Y= 180°-60°

therefore, angle Y =120°.

hope it helped..

5 0

3 years ago

3x - 2y = -1

DIA [1.3K]

Answer:

nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

Step-by-step explanation:

3 0

3 years ago

In the vector space <img src="https://tex.z-dn.net/?f=P_2%28%5Cmathbb%7BR%7D%29" id="TexFormula1" title="P_2(\mathbb{R})" alt="P

tatuchka [14]

We could express any vector $p\in P_2(\mathbb R)$ as

$p=ax^2+bx+c$

So any vector $u\in U$ would have coefficients $a,b,c$ that satisfy

$16a+4b+c=0\implies c=-16a-4b$

from which we can show that any such vector is a linear combination of some other vectors:

$u=ax^2+bx+(-16a-4b)=a(x^2-16)+b(x-4)$

More explicitly, we've shown that $u$ is a linear combination of the vectors $x^2-16$ and $x-4$ ; in other words, $u\in\mathrm{span}\{x^2-16,x-4\}$ , and in fact these two vectors form a basis for $U$ . But this set does not span all of $P_2(\mathbb R)$ because there's no combination of these two vectors that can be used to obtain a constant. We want the transformation to be usable for any vector in $P_2(\mathbb R)$ , so we need to add an additional vector extend the basis. We can do this simply by appending $1$ into the spanning set. (Do check that the vectors remain linearly independent.)

Now we want the transformation to map those polynomials $p(x)$ for which $p(4)=0$ to the zero vector. We know which vectors belong to the basis of $U$ , so we need

$f(x^2-16)=0$

$f(x-4)=0$

$f(1)=1$

where the choice of the assignment for $f(1)$ is arbitrary, so long as it's non-zero.

6 0

3 years ago