i believe its true but idk lol hope this helps :)
C) <em>The frequency of heterozygotes is given by (p + q)/N, where N is the number of individuals in the population.</em>
Answer:
There's 25% probability that their next child will be normal, and 75% of it being a dwarf.
Explanation:
Achondroplasia (A) is a dominant trait.
Two achondroplastic dwarfs (A_ x A_) have a dwarf child (A_) and a normal child (aa). The second child must be aa because if it had a dominant allele it would also be dwarf.
The only way for two achondroplastic parents to have a normal child is that <u>they are both heterozygous (Aa) for this gene.</u>
The cross Aa x Aa would produce the following offspring probabilities:
- 1/4 AA - dwarf
- 2/4 Aa - dwarf
- 1/4 aa - normal
So there's 1/4=25% probability that their next child will be normal, and 3/4=75% of it being a dwarf.
<span>south American temperate plants were more similar to the tropical plants of South America than to the temperate plants of Europe</span>
