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2 years ago

5

The length of a rectangle is a centimeters, and the width of this rectangle is b centimeters. Write an expression for the area o

f the rectangle. "a" and "b" are variables.

1 answer:

Novay_Z [31]2 years ago

7 0

Answer:

Area = ab

Step-by-step explanation:

Area is length × width, so fill in a for the length and b for the width. Multiply a and b together.

A = a×b

A = ab

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Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean

Leno4ka [110]

Answer:

a = $\sqrt{7}$

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.:

<em>Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4</em>.

My answer:

We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

$a^2+b^2=c^2$

Given that: b=3 and c=4

$a^2+3^2=4^2a^2+9=16a^2+9-9=16-9a^2=7$

so a = $\sqrt{7}$

We know that tangent relates opposite side of a right triangle with adjacent side.

$\text{tan}(B)=\frac{a}{b}\\\text{tan}(B)=\frac{\sqrt{7}}{3}$

Please have a look at the attached photos.

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3 years ago

HELPPP PLZZZZ ASAP IS PLEASEEE DONT SEND A FILE AT ALL

jeka57 [31]

Answer:

(-5, 7)

Step-by-step explanation:

Translate A left 6, and up 4

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2 years ago

The data below are the ages and systolic blood pressures (measured in millimeters of mercury) of 9 randomly selected adults. Wha

seraphim [82]

Answer:

$\sum_{i=1}^n x_i =459$

$\sum_{i=1}^n y_i =1227$

$\sum_{i=1}^n x^2_i =24059$

$\sum_{i=1}^n y^2_i =168843$

$\sum_{i=1}^n x_i y_i =63544$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=24059-\frac{459^2}{9}=650$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=63544-\frac{459*1227}{9}=967$

And the slope would be:

$m=\frac{967}{650}=1.488$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{459}{9}=51$

$\bar y= \frac{\sum y_i}{n}=\frac{1227}{9}=136.33$

And we can find the intercept using this:

$b=\bar y -m \bar x=136.33-(1.488*51)=60.442$

So the line would be given by:

$y=1.488 x +60.442$

And then the best predicted value of y for x = 41 is:

$y=1.488*41 +60.442 =121.45$

Step-by-step explanation:

For this case we assume the following dataset given:

x: 38,41,45,48,51,53,57,61,65

y: 116,120,123,131,142,145,148,150,152

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i =459$

$\sum_{i=1}^n y_i =1227$

$\sum_{i=1}^n x^2_i =24059$

$\sum_{i=1}^n y^2_i =168843$

$\sum_{i=1}^n x_i y_i =63544$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=24059-\frac{459^2}{9}=650$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=63544-\frac{459*1227}{9}=967$

And the slope would be:

$m=\frac{967}{650}=1.488$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{459}{9}=51$

$\bar y= \frac{\sum y_i}{n}=\frac{1227}{9}=136.33$

And we can find the intercept using this:

$b=\bar y -m \bar x=136.33-(1.488*51)=60.442$

So the line would be given by:

$y=1.488 x +60.442$

And then the best predicted value of y for x = 41 is:

$y=1.488*41 +60.442 =121.45$

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3 years ago

HELP ME PLEASE !!!!!!!!!!!!!!!

Slav-nsk [51]

Answer:

1. y = x + 3

2. y = $\frac{2}{3}$ x -6

3. y = x - 1

4. y = -2x -2

5. y = 2x - 1

6. y = $\frac{1}{2}$ x - 4

7. y = -x

8. y = $\frac{-3}{2}$ x + 1

Step-by-step explanation:

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3 years ago

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USPshnik [31]

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3 years ago

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