Answer:
ax² + bx + c
Step-by-step explanation:
The form of a quadratic equation that is easy to use when finding the maximum or minimum value of the function is ax² + bx + c.
Suppose a quadratic function:
f(x) = 2x² - 8x + 9
Use ( -b/2a , f(-b/2a) ).
-b/2a
a = 2
b = -8
-(-8)/2(2)
8/4
= 2
f(2) = 2(2)² - 8(2) + 9
f(2) = 2(4) - 8(2) + 9
f(2) = 8 - 16 + 9
f(2) = 1
The minimum value of this quadratic function is (2, 1).
It represents a minimum value because a > 0.
The easiest way to prove equivalence is to draw out a truth table and then compare the values. I'm going to show a truth table using proposition logic, it's the same result as using predicate logic.
P(x) v Q(x)
P |Q || PvQ || ~Q->P <----Notice how this column matches the PvQ but if you were to
---|---||--------||---------- <----continue the truth table with ~P->Q it would not be equivalent
T T T T
T F T T
F T T T
F F F F
Let me know if you would like an example, if the truth table doesn't help.
A^2 + b^2 = c^2....this is the pythagoream theroum (sorry, probably spelled it wrong)....it is used for right triangles.
a and b are ur legs of the triangle and c is the hypotenuse. Therefore, the value of a^2 is the value of one of the legs, squared.
OR. if u mean this..
a^2 + b^2 = c^2
a^2 = c^2 - b^2
Y=2x-5.
I found the slope using the formula m=y2-y1/x2-x1.
m=-3-1/1-3=-4/-2=2.
I used (3,1) (only use one point, your choice) to find out b. 3=x, 1=y.
y=mx+b is the formula for slope intercept equations, so I plugged in the x and y.
1=2(3)+b; 1=6+b, subtract 6 on both sides and get -5=b.
I used the information to get y=2x-5.
Hope this isn’t too confusing! :)
Step-by-step explanation:
siht daer tnod
