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Inessa [10]
2 years ago
14

Marsha's house is located on the coordinate plane below. Tasha's house is located 6 units from Marsha's house. Which of the foll

owing could represent the location of Tasha's house?

Mathematics
1 answer:
Gekata [30.6K]2 years ago
3 0

B 4,2 because it is 6 units away from the point

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F(x) = 2x - 3 and f(x) = f'(x), find the value of x.​
Salsk061 [2.6K]

Answer:

x=1

Step-by-step explanation:

According to your typed question,

f(x)=2x-3

Let f(x)=y

y=2x-3

Now,

Interchanging the positions of x and y

x=2y-3

x+3=2y

x+3/2=y

f'(x)=x+3/2

Then,

f(x)=f'(x)

2x-3=x+3/2

2(2x-3)=x+3

4x-3=x+3

4x-x=3+3

3x=3

x=3/3

x=1

According to your image question,

f(x)=x/2x-3

f(x)=f'(x)

Now,

Let y=f(x)

y=x/2x-3

y(2x-3)=x

2xy-3=x

2xy-x=3

x(2y-1)=3

2y-1=3x

2y=3x+1

y=3x+1/2

f'(x)=3x+1/2

Then,

f(x)=f'(x)

x/2x-3=3x+1/2

2x=6xsq+2x-9x+3

2x=6xsq+7x+3

solve for x ok

8 0
3 years ago
On the grid draw a scaled copy of quadrilateral ABCD with a scale factor 2/3
Tamiku [17]

Answer:

Attached diagram A'B'C'D'

Step-by-step explanation:

Given is a quadrilateral ABCD. It says to draw a dilated version with a scale factor 2/3.

We see that scale factor is less than 1 which means it shrinks the image to a smaller one.

To draw a scaled copy, we need to find the lengths of its sides.

To do so, we can draw the diagonals AC & BD, and they intersect at origin O(0,0) such that OA= -2, OB= 2, OC= 4, OD= -4.

Applying a scale factor of 2/3, we get OA' = -4/3, OB' = 4/3, OC' = 8/3, OD' = -8/3.

So we have attached a scaled copy A'B'C'D' of quadrilateral ABCD with a scale factor 2/3.

6 0
2 years ago
During one waiter’s shift, he delivered 13 appetizers, 17 entrées, and 10 desserts.
Romashka-Z-Leto [24]

Answer:

whats the question

Step-by-step explanation:

will be edited when answered

5 0
3 years ago
Read 2 more answers
Middle School: Math (10 Points)
sasho [114]
1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:

A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?

You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked

2) a - 2%  as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.  

b - 1,000,000/2500 = 400
400 packages are defective each year
5 0
3 years ago
A closet contains 8 pairs of pants, 10 shirts, and 4 pairs of shoes. How many leaves on a tree diagram would represent all possi
EleoNora [17]
The answer is, there are 320 possible combinations of outfits
7 0
3 years ago
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