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anzhelika [568]
3 years ago
11

A pilot took 1/2 hours to complete his 1/3 pf his ttip how much longer will it take him to complete his trip?

Mathematics
1 answer:
Norma-Jean [14]3 years ago
7 0

Answer:

1.5 hours

Step-by-step explanation:

1/2 + 1/2 + 1/2 =1.5

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a cargo ship travel 150 mi in 6 hours at a constant speed how far did the cargo ship travel in 1 hour​
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25mi

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3 years ago
(a) Find the equation of the normal to the hyperbola x = 4t, y = 4/t at the point (8,2).
gtnhenbr [62]

The slope of the tangent line to the curve at (8, 2) is given by the derivative \frac{dy}{dx} at that point. By the chain rule,

\dfrac{dy}{dx} = \dfrac{dy}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{dy}{dt}}{\frac{dx}{dt}}

Differentiate the given parametric equations with respect to t :

x = 4t \implies \dfrac{dx}{dt} = 4

y = \dfrac4t \implies \dfrac{dy}{dt} = -\dfrac4{t^2}

Then

\dfrac{dy}{dx} = \dfrac{-\frac4{t^2}}4 = -\dfrac1{t^2}

We have x=8 and y=2 when t=2, so the slope at the given point is \frac{dy}{dx} = -\frac14.

The normal line to the same point is perpendicular to the tangent line, so its slope is +4. Then using the point-slope formula for a line, the normal line has equation

y - 2 = 4 (x - 8) \implies \boxed{y = 4x - 30}

Alternatively, we can eliminate the parameter and express y explicitly in terms of x :

x = 4t \implies t = \dfrac x4 \implies y = \dfrac4t = \dfrac4{\frac x4} = \dfrac{16}x

Then the slope of the tangent line is

\dfrac{dy}{dx} = -\dfrac{16}{x^2}

At x = 8, the slope is again -\frac{16}{64}=-\frac14, so the normal has slope +4, and so on.

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2 years ago
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Step-by-step explanation:

A/B=5/7 , B/C=6/12

Taking B=12×7=84, we get

A=12×5=60, C=7×6=42

Hence,

60:84:42. Answer

3 0
3 years ago
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