Given:
In triangle XYZ, x = 27 cm, y = 79 cm and
.
To find:
The length of z.
Solution:
In triangle XYZ, using the Law of cosine, we get
![z^2=x^2+y^2-2xy\cos Z](https://tex.z-dn.net/?f=z%5E2%3Dx%5E2%2By%5E2-2xy%5Ccos%20Z)
Putting the given values in the above formula, we get
![z^2=(27)^2+(79)^2-2(27)(79)\cos (142^\circ)](https://tex.z-dn.net/?f=z%5E2%3D%2827%29%5E2%2B%2879%29%5E2-2%2827%29%2879%29%5Ccos%20%28142%5E%5Ccirc%29)
![z^2=729+6241-4266(-0.788)](https://tex.z-dn.net/?f=z%5E2%3D729%2B6241-4266%28-0.788%29)
![z^2=6970+3361.608](https://tex.z-dn.net/?f=z%5E2%3D6970%2B3361.608)
![z^2=10331.608](https://tex.z-dn.net/?f=z%5E2%3D10331.608)
Taking square root on both sides.
![z=\pm \sqrt{10331.608}](https://tex.z-dn.net/?f=z%3D%5Cpm%20%5Csqrt%7B10331.608%7D)
![z=\pm 101.6445178](https://tex.z-dn.net/?f=z%3D%5Cpm%20101.6445178)
Approx the above value to the nearest number and side length cannot be negative. So,
![z\approx \pm 102\text{ cm}](https://tex.z-dn.net/?f=z%5Capprox%20%5Cpm%20102%5Ctext%7B%20cm%7D)
Therefore, the length of z is about 102 cm.
Answer:
A. 7
B.−16x^2+10x−19y−56
Explanation:
A. In the first attachment
B. In the second attachment
Answer:
see below (I hope this helps!)
Step-by-step explanation:
Whole numbers are the integers that are greater or equal to 0. Basically, they are 0, 1, 2, 3....
Rational numbers can be written in the form a / b (where b ≠ 0 and a and b are integers (integers are ..., -1, 0, 1, ...))
Therefore, 4 rational numbers that are not whole numbers could be -5, -1, 0.5, and 3/4.
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