Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
im pretty sure The answer is 45
Answer:
I am just doing it for points
Step-by-step explanation:
The answer is blah blah blah
Answer:
A
Step-by-step explanation:
A is an arithmetic sequence with first term -2 and common difference 5. Each new term is found by adding 5 to the previous term.
B is a geometric sequence with first term 1 and common ratio 1/2.
C is neither an arithmetic nor a geometric sequence.
D is neither. We might call it an "alternating sequence."
Answer:
I don't know ur Language .......
