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Solnce55 [7]
3 years ago
15

how much wrapping paper would you need to cover a rectangular that is 18.25 inches by 12inches by 3 inches if you need 10% more

wrapping paper than the surface area of the box? give your answer to the nearest square inch​
Mathematics
1 answer:
natita [175]3 years ago
4 0

Answer: 681 square inch

Step-by-step explanation:

Hi, we have to apply the formula for the surface area:

A = 2wl + 2lh + 2hw

Where:

w: width

l: length

h: height

Replacing with the values given:

A = (2x12x18.25) + (2x12x3)+(2x18.25x3)

A= 438+72+109.25

A=619.5 in2

Since it has to be 10% more than the surface.

619.5 x (10/100) = 61.95 in2

Adding that value to the surface area

619.5+61.95 = 681.45in2 = 681 in2

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<em></em>

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Null Hypothesis is what is given and Alternate is what we are testing.

Since Null Hypothesis is given that the mean weight is GREATER THAN 40 pounds, the ALTERNATE HYPOTHESIS would be the mean weight is either EQUAL TO or LESS THAN 40 pounds.

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