The amount earned from the local account must be greater than that of the online account.
Amount from local account = 6,500(1.0145)ⁿ
Amount from online account = 6,500(1.0225)ⁿ - 4x
Where n is the number of years and x is the number of ATM withdrawals.
6,500(1.0145)ⁿ > 6,500(1.0225)ⁿ - 4x
4x > 6,500[(1.0225)ⁿ - (1.0145)ⁿ]; n = 1
x > 13
The number of withdrawals must exceed 13.
The answer is C.
The answer is C, factor out the equation to be (x-3)(x+2) and you would get x= 3 and -2 but since x has to be greater than y it can only be 3
A, as absolute value refers to distance a number is from 0 whether it be neg or pos
Step-by-step explanation:
to find his total expenses, add all fraction spent
3/8 + 1/3 + 1/6
= 9+8+ 4/24
= 21/24. = 7/8
total fraction =1
subtract the fraction spent form the total fraction to know the fraction left for savings
1-7/8= 1/8
therefore if. 1 = 2,400
then 1/8=?
if less more divides
1/8 ÷ 1 ×2,400
1/8 × 1/1×2,400
1/8 × 2,400
=300.
therefore the man saved 300 rupees
