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Sunny_sXe [5.5K]
2 years ago
9

Your cell phone bill is $40.00 you have a coupon for 5% off what is the new total

Mathematics
1 answer:
trasher [3.6K]2 years ago
5 0
The new total is 38 dollars
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Which chocolate chip cookies have the greater spread in the number of chips per cookie?
Arisa [49]

Step-by-step explanation:

18

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2 years ago
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What is the equation of a line that is perpendicular to -1 +3y=9 and passes through the point (-3, 2)?​
kati45 [8]

Answer:

y-2 = 3/10(x+3)

Step-by-step explanation:

3y = 10

y = 10/3

looking for perpendicular so slope = 3/10

using the given point

y-2 = 3/10(x+3)

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2 years ago
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he isosceles triangle has a perimeter of 7.5 m. Which equation can be used to find the value of x if the shortest side, y, measu
lapo4ka [179]

Answer:

2x+ 2.1 = 7.5

x=2.7

Step-by-step explanation:

The perimeter of an isosceles triangle with sides x and y is

2x+y = P

I put y as the single side since the question said y is the shortest side.  It should say shorter sides if the two sides with the same length are smaller than the third.

We know y =2.1 and P = 7.5

Substituting these values in, we get

2x+ 2.1 = 7.5

Subtract 2.1 from each side

2x+2.1 -2.1 = 7.5 -2.1

2x= 5.4

Divide each side by 2

2x/2 = 5.4/2

x = 2.7 m



3 0
3 years ago
What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?
Molodets [167]
The answer to this is 
x= 18, -2
3 0
2 years ago
A ball is launched from 8 yards off the ground and travels in parabolic motion, landing in a net 80 yards away and also 8 yards
Masteriza [31]

Answer:

The answer to this question is the wall is 45.95 yards tall

Step-by-step explanation:

To solve this, we list out the given variables and the unknowns thus

Height of ball at launch = 8 yards

Distance of net from the ball = 80 yards

Distance of the wall down the path = 75%

Maximum height of the ball= 80 yards

equation of Motion of the ball = parabolic motion =

v² = u² - 2gS

S = 80 - 8 = 72 yards

at maximum height v = 0 thus u² = 2×9.81×72 =1412.64

u = 37.59 m/s

also v = u - gt and again at max height v = 0

Therefore 37.59 = 9.81×t or t = 3.83 s

If the motion of the ball is free of obstruction then time of flight before the ball just reaches the 8 yards off the ground = 3.83×2 = 7.66 seconds

Taking the initial velocity as zero at maximum height and from the equation

S = ut + 0.5×gt² we get, where S is the heigt of the ball from touching the actual field ground which is 80 yards we have

80 = 0.5×9.81×t²

so that t² = 2×80÷9.81 = 16.31 or t = 4.04s

Therefore the total time of flight = 4.04 + 3.83 = 7.87 seconds

if the ball is considered as having a constant horizontal velocity, therefore

at 75% of the way the time it took will be 0.75×7.87 = 5.9 seconds

However time it took  the  ball to reach maximum height and then starts descent = 3.83s, and the time at which the ball is directly over the wall = 2.07 seconds on the second half just after reaching mximum height

Thus at 2.07 seconds the distance trvelled from the maximum height is

S = ut +0.5gt² as before where u = 0

hence S = 0.5×9.81×2.07² = 21.05 yards or (80 -21.05) yards off the ground =  58.95 yards

As stated in the question, the ball cleared the wall by 13 yards therefore the height of the wall is 58.95 - 13 = 45.95 yards

7 0
2 years ago
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