Ask question

Ask question

All categories

1 year ago

8

The area of a quadrilateral whose vertices is ABCD taken in order are (1,2) (-5,6) (7,-4) and (-2,t) be 0 ,find the value of t

1 answer:

AfilCa [17]1 year ago

3 0

Coordinates : A(1,2) B(-5,6) C(7,-4) D(-2,t) - All are taken in order

gradient of AB = (6-2)/(-5-1) = 4/-6 = -⅔
since it is quadrilateral, AB//CD
gradient of CD = -⅔
equation of CD : y-(-4)=-⅔(x-7)
y+4=-⅔x+14/3
y=-⅔x+⅔
now, sub x=-2 from D(-2,t)
since t is the y-coordinate of point D
t=-⅔(-2)+⅔
t=2

Therefore, t=2

You might be interested in

Nnnooooo liinnkkkks

Arturiano [62]

The answer I believe is c

7 0

2 years ago

Read 2 more answers

Recall that the graph of a function f is the graph of the set of ordered pairs (x,f(x))

Simora [160]

$y=f(x)+12$

7 0

3 years ago

What is (n+2) / -8=-4

Travka [436]

$\frac{n +2}{-8} =-4$ Multiply -8 on both sides

$\frac{n +2}{-8} (-8)=-4(-8)$

n + 2 = 32 Subtract 2 on both sides

n + 2 - 2 = 32 - 2

n = 30

5 0

2 years ago

Please solve this equations y=6x²-5,y=17x-6/x

Amiraneli [1.4K]

Answer:

$x=3, y = 49\\x=0.5, y = -3.5\\x=-0.67, y = -2.31$

Step-by-step explanation:

$y=6x^2-5\\y=17x-\frac{6}{x}$

Let's substitute the first equation into the second one.

$6x^2-5=17x-\frac{6}{x}$

$6x^3-17x^2-5x+6=0$ - Multiply by $x$ and bring all the terms to one side.

I'll use my graphical calculator to solve this but you could factor:

$x=3\\x=0.5\\x=-0.67$ (All rounded to 2 decimal places)

Now we can substitute these $x$ values into an equation for $y$ .

$y=6x^2 - 5$

$x=3, y = 49\\x=0.5, y = -3.5\\x=-0.67, y = -2.31$

5 0

2 years ago

five times the sum of a number and 27 is greater than or equal to six times the sum of the number and 26 what is the solution to

zvonat [6]

5(n + 27) >= 6(n + 26)

5n + 135 >= 6n + 156

-n >= 21

n <= -21

6 0

2 years ago