Answer:
<u>Kathy drove the first 9 hours of the trip and Brian drove the last 3 hours.</u>
Step-by-step explanation:
Let's review the information given to us to answer the question correctly:
Total distance of the trip = 750 miles
Time of the trip = 12 hours
Speed of Kathy = 65 mph
Speed of Brian = 55 mph
2. For what length of the time did Kathy and Brian drive?
Let's solve the problem, this way:
x = Time in hours Kathy drove
12 - x = Time in hours Brian drove
Now, let's write our equation to solve for x:
65x + 55 (12 - x) = 750
65x + 660 - 55x = 750
10x = 750 - 660
10x = 90
x = 90/10
x = 9 ⇒ 12 - x = 3
<u>Kathy drove the first 9 hours of the trip and Brian drove the last 3 hours.</u>
25 is 5 more than 20 which is 25% more since 5/20 = 1/4 = 25%
To check (1.25 * 20 = 25)
The mean is 13.5 and the median is 5.5
No.
So, there are 1000 milligrams in one gram, making the 4000 mgs equal to 4 grams.
There are 1000 grams in one kilogram, so 4 kilograms is equal to 4000 grams.
4000 =/= 4
So, 4 kilograms and 4000 milligrams are not equal.
Answer:
Step-by-step explanation:
11) strategy: since they tell us. indirectly, that the length of JK is the same as LM then we can set those two equal, solve for X and then.. when we have X we can figure out the lenght of JK and LM and then just divide that by 2 go get PK ( :0 Player Killer ??? no , not that PK)
solve JK and LM
3x + 23 =9x-19
42 = 6x
7 = x
now that we know x = 7 plug it into either equation to come up with the length of JK or LM . I'll pick JK just b/c it was 1st
3(7) + 23 = JK
21+23 = JK
44 = JK
now take half of 1/2*JK= 22 that is PK ( are you sure that 's not player killer?)
PK = 22
12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB
9x-20 = 5x + 28
4x = 48
X = 12
9(12) -20 = BG
88 = BG
2*88 + AB
176 = AB
13) done
14) strategy: find the angle at L, and that will also be the arc of MK
<em>copy and past the below</em> helpful trig functions into your computer
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
<em>copy and past the above</em> :
use which ever trig function you want , we have all the sides of the triangle, I'll use CAH
Cos(Ф) = 9/15
Ф = arcCos(9/15)
Ф = 53.13010°
arc MK = 53.13010°
15) strategy: arc JK is just 2 times MK
2*MK = 106.26020°
arc MK = 106.26020°
16) find arc JPK strategy: JPK is just the remaining part of a full circle of 360 - MK = 253.7397°
arc JPK = 253.7397°
