Answer:
<h3>2.5secs</h3>
Step-by-step explanation:
Given the height of the ball modeled by the equation h = -16t^2+ 100, where
h is the height
t is in seconds
We can find the time taken by the ball to reach the ground.
The ball reaches the ground when the height h = 0
Substitute h = 0 into the equation and find t;
0 = -16t^2+ 100
16t^2 = 100
t^2 = 100/16
t = √100/16
t = 10/4
t = 2.5secs
Hence the ball reaches the ground after 2.5secs
Answer:
The correct option is <u>c) $17.50/case</u>.
Step-by-step explanation:
Note: The data in the question are merged. The data are therefore sorted and the whole question is represented before answering the question. Please, see the attached pdf file for the sorted data and the represented question.
The explanation of the answer is now given as follows:
Marginal cost refers to the cost incurred in order to produce one more unit of a product.
Therefore, marginal cost is the change in the total cost that is caused by a one-unit increase in the quantity of a commodity that is produced.
From the table in the question, the marginal cost at q = 108 can be calculated as follows:
Change in total quantity at 180 cases = 108 - Number of cases immediately before 108 = 180 - 104 = 4
Change in total cost at 180 cases = Total cost at 108 cases - Total cost immediately before 108 cases = 1990 - 1920 = 70
Marginal cost at 108 cases = Change in total cost at 180 cases / Change in total quantity at 180 cases = 70 / 4 = 17.50 per case
Therefore, the correct option is <u>c) $17.50/case</u>.
A central angle:
α = 170°
d = 9.1 cm
r = 9.1 : 2 = 4.55 cm
Area of a sector:
A = r² π α / 360°
A = ( 4.55 )² · 3.14 · 170° / 360°
A = 30.7 cm²
0.9 x (12-2) + 0.6
0.9 x (14) + 0.6
12.6 + 0.6
13.2
I hope I helped
Please make me brainliest
D is the answer because 2+5 = 7 and ya
