Question

Find the area of a sector with a central angle of 170° and a diameter of 9.1 cm. Round to the nearest tenth.

Answer 1

A central angle:
α = 170°
d = 9.1 cm
r = 9.1 : 2 = 4.55 cm
Area of a sector:
A = r² π α / 360°
A = ( 4.55 )² · 3.14 · 170° / 360°
A = 30.7 cm²

Answer 2

Answer:

The area of sector is 30.7 cm².

Step-by-step explanation:

The diameter of a circle is 9.1 cm, so the radius of the circle is

$r=\frac{d}{2}=\frac{9.1}{2}=4.55$

The central angle of a sector is 170°.

The area of a sector is

$A=\pi r^2\times (\frac{\theta}{360})$

Where, r is radius and θ is central angle.

$A=\pi (4.55)^2\times (\frac{170}{360})$

$A=30.712777$

$A\approx 30.7$

Therefore the area of sector is 30.7 cm².