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Damm [24]
3 years ago
5

Find the area of a sector with a central angle of 170° and a diameter of 9.1 cm. Round to the nearest tenth.

Mathematics
2 answers:
Nesterboy [21]3 years ago
6 0
A central angle:
α = 170°
d = 9.1 cm
r = 9.1 : 2 = 4.55 cm
Area of a sector:
A = r² π α / 360°
A = ( 4.55 )² · 3.14 · 170° / 360°
A = 30.7 cm²
ehidna [41]3 years ago
3 0

Answer:

The area of sector is 30.7 cm².

Step-by-step explanation:

The diameter of a circle is 9.1 cm, so the radius of the circle is

r=\frac{d}{2}=\frac{9.1}{2}=4.55

The central angle of a sector is 170°.

The area of a sector is

A=\pi r^2\times (\frac{\theta}{360})

Where, r is radius and θ is central angle.

A=\pi (4.55)^2\times (\frac{170}{360})

A=30.712777

A\approx 30.7

Therefore the area of sector is 30.7 cm².

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nikitadnepr [17]

ANSWER : 9 over 4

or 2 and 1/4

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*3 over 2 x 3 over 2 is 3/2 x 3/2* << this is for me to remember

Okay so multiplying fractions means for us to multiply across. That means if we line the fractions, we multiply. Like this

 3     x     3

-----         -----                3 times 3 is = 9

 2     x     2                  2 times 2 is = 4

9 over 4 is the same thing as 2 and 1/4  << FRACTION    

                                                ^^      

                                           WHOLE

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8 0
3 years ago
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Svetradugi [14.3K]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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5 0
1 year ago
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Answer:

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Step-by-step explanation:

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Here's the work;

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