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vichka [17]
2 years ago
8

26. A network administrator is looking to expand the available bandwidth of his extranet remote branch by adding another leased

line. The ISP has notified the administrator that another physical serial connection will need to be added to his gateway router. Which of the following will realise this?
A. Add a distribution layer card into the router allowing another gigabit ethernet port.
B. Add a layer 3 switch into the network.
C. Install a WAN interface card with appropriate interface connectors to the
router.
D. Multiplex the existing serial using the appropriate commands in the config
file.



27. What happens after configure a rule with IP address 0.0.0.0 and wildcard mask 255.255.255.255?
A. This is default configuration B. Block all IP address
C. Allow all IP addresses
D. Nothing will happens
Computers and Technology
1 answer:
Talja [164]2 years ago
5 0

The option that will realize the above case is that  Add a distribution layer card into the router allowing another gigabit ethernet port.

<h3>How do one  Increase Bandwidth on Router</h3>

The steps are:

  • Alter the Router's Location.
  • Then Reboot your Router.
  • Have a Dual-bandwidth Router.
  • Then do Update the Router's Firmware.

So therefore, The option that will realize the above case is that  Add a distribution layer card into the router allowing another gigabit ethernet port.

Learn more about expanding bandwidth from

brainly.com/question/25898149

#SPJ1

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3 years ago
Which of the following would be a valid method call for the following method? public static void showProduct (int num1, double n
Alenkinab [10]

Answer:

showProduct(int,double)

for example: showProduct(10,10.5) is the correct answer even showProduct(10,10.0) is also correct but showProduct(10.0,10.5) or showProduct(10,10) or showProduct(10.0,10) are wrong calls.

Explanation:

The code is

  1.       <em>public static void showProduct (int num1, double num2){</em>
  2. <em>       int product;</em>
  3. <em>       product = num1*(int)num2;</em>
  4. <em>       System.out.println("The product is "+product);</em>
  5. <em>       }</em>

showProduct is function which asks for two arguments whenever it is called, first one is integer and second one is of type double which is nothing but decimal point numbers. Generally, in programming languages, 10 is treated as integer but 10.0 is treated as decimal point number, but in real life they are same.

If showProduct( 10,10.0) is called the output will be 'The product is 100'.

Strange fact is that, if you enter showProduct(10,10.5) the output will remain same as 'The product is 100'. This happens because in the 3rd line of code,which is <em>product=num1*(int)num2</em>, (int) is placed before num2 which makes num2 as of type integer, which means whatever the value of num2 two is given, numbers after decimal is erased and only the integer part is used there.

This is necessary in JAVA and many other programming languages as you <u>cannot</u><u> multiply two different datatypes</u> (here one is int and another is double). Either both of them should be of type int or both should be of type double.

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