Answer:
The correct selection is the letter C. The first ACL is denying all TCP traffic and the other ACLs are being ignored by the router.
Explanation:
In this case, the letter C is the right answer because with the first ACL exactly:
access-list 102 deny tcp any any
We are denying all traffic with the next line deny tcp any any, in this case, the others line are being ignored.
access-list 104 permit udp host 10.0.0.3 any
access-list 110 permit tcp host 10.0.0.2 eq www any
access-list 108 permit tcp any eq ftp any
For that nobody can access to the internet, the security administrator of ABC must change the first ACL.
YOU COULD POTTENTIALLY HAVE TO WIPE ALL CURRENT FILES CLEAN OR U MAY HAVE TO PAY FOR CERTAIN PROGRAMS
Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
class Window //defining a class Window
{
private:
int width, height;//defining integer variable
public:
friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters
{
return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values
}
Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters
{}
};
int main() //Main method
{
Window w(80,90);//calling class constructor
cout<<w;//print object value
return 0;
}
Output:
a (80 x 90) window
Explanation:
In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.
Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.
