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Helga [31]
3 years ago
9

My PC won't output any data does anyone have any ideas​

Computers and Technology
1 answer:
pav-90 [236]3 years ago
4 0
Have you tried using a different drive?
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OSI layer for HDLC??​
tresset_1 [31]

Answer:

HDLC is one of the most commonly used internet protocols (IP) in what is Layer 2 of the industry communication reference model called Open Systems Interconnection (OSI).

Explanation:

3 0
3 years ago
On the seventh day of the iteration, the team realizes that they will not complete 5 of the 13 stories. the product owner says s
nika2105 [10]

Answer:

First of all the team should excuse to the product owner for not being responsible and committed to the deadline.

Secondly, as they have completed the 8 stories, so they should revise and check the flaws in those stories and send to her.

Because when the product owner will check and happy with them, she will surely discuss the remaining stories with the team.

6 0
4 years ago
Consider two different implementations, M1 and M2, of the same instruction set. There are three classes of instructions (A, B, a
Margaret [11]

Explanation:

A.)

we have two machines M1 and M2

cpi stands for clocks per instruction.

to get cpi for machine 1:

= we multiply frequencies with their corresponding M1 cycles and add everything up

50/100 x 1 = 0.5

20/100 x 2 = 0.4

30/100 x 3 = 0.9

CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8

We find CPI for machine 2

we use the same formula we used for 1 above

50/100 x 2 = 1

20/100 x 3 = 0.6

30/100 x 4 = 1.2

CPI for m2 =  1 + 0.6 + 1.2 = 2.8

B.)

CPU execution time for m1 and m2

this is calculated by using the formula;

I * CPI/clock cycle time

execution time for A:

= I * 1.8/60X10⁶

= I x 30 nsec

execution time b:

I x 2.8/80x10⁶

= I x 35 nsec

6 0
3 years ago
Within MethodsPractice.java, write a method public static int planParty2(int f, int c, int p) that performs the same calculation
Vesna [10]

Answer:

// class definition of MethodPractice

public class MethodPractice {

   // main method that begin program execution

   public static void main(String args[]) {

       // call to the planParty2 method is done using some parameter

       // and the return value is displayed

     System.out.println("The number of p-packs needed is: " + planParty2(9, 14, 6));

     System.out.println("The number of p-packs needed is: " + planParty2(4, 6, 3));

     System.out.println("The number of p-packs needed is: " + planParty2(4, 6, 4));

   }

   

   // planParty2 method with 3 parameters and it return an integer

   // the calculation needed to get the required pack is done here

   public static int planParty2(int f, int c, int p){

       // the party owner is added to list of friend

       // and the value is assigned to totalPeople

       int totalPeople = f + 1;

       // the totalPeople times the can drink

       // is assigned to totalDrinkNeeded

       int totalDrinkNeeded = totalPeople * c;

       // number of packs required is declared

       int numberOfPacks;

       // if the totalDrinkNeeded contains exact multiple of a pack

       // we return the numberOfPack by dividing totalDrinkNeeded with p

       if (totalDrinkNeeded % p == 0){

           return numberOfPacks = totalDrinkNeeded / p;

       }

       // else we compute if the totalDrinkNeeded is not a multiple of a pack

       //  first we get the remainder when the totalDrinkNeeded is divided with p

       // then the needed can is computed by subtracting remainder from p

       // the neededCan is added to totalDrinkNeeded, then divided with p

       // and assigned to numberOfPacks

       // numberOfPacks is returned.

       else {

           int remainder = totalDrinkNeeded % p;

           int neededCan = p - remainder;

           numberOfPacks = (totalDrinkNeeded + neededCan) / p;

           return numberOfPacks;

       }

   }

}

Explanation:

Image showing the detailed question is attached.

The program is written in Java and is well commented. A sample image of program output when it is executed is attached.

3 0
3 years ago
“The software crisis is aggravated by the progress in hardware technology?” Explain with examples
exis [7]

Answer:

Basically, dealing with the "software crisis" is what we now call software engineering. We just see the field more clearly now.

What this crisis was all about is that in the early days of the modern technological era -- in the 1950s, say -- there was tremendous optimism about the effect that digital computers could have on society, on their ability to literally solve humanity's problems. We just needed to formalize important questions and let our hulking "digital brains" come up with the answers.

Artificial intelligence, for example, had some early successes in easy to formalize domains like chess and these sorts of successes led to lots of people who should have known better making extremely naive predictions about how soon perfect machine translation would transform human interaction and how soon rote and onerous work would be relegated to the dustbin of history by autonomous intelligent machines.

7 0
2 years ago
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