Answer:
SELECT Count(order_invoice) as number_of_invoices, Max(order_invoice) as maximum_invoice, Min(order_invoice) as minimum_invoice, Avg(order_invoice) as average_invoice
FROM vendor JOIN invoice ON invoice.id = vendor.id
WHERE order_invoice > 1
ORDER BY number_of_invoices DESC
Explanation:
The select statement of the SQL or structured query language returns twelve rows of four columns from the inner join of the vendor and invoice table in a database where the order_invoice column in the invoice table is greater than one. The result of the query is ordered by the alias column "number_of_invoices" in descending order.
Answer:
In C++:
int PrintInBinary(int num){
if (num == 0)
return 0;
else
return (num % 2 + 10 * PrintInBinary(num / 2));
}
Explanation:
This defines the PrintInBinary function
int PrintInBinary(int num){
This returns 0 is num is 0 or num has been reduced to 0
<em> if (num == 0) </em>
<em> return 0; </em>
If otherwise, see below for further explanation
<em> else
</em>
<em> return (num % 2 + 10 * PrintInBinary(num / 2));
</em>
}
----------------------------------------------------------------------------------------
num % 2 + 10 * PrintInBinary(num / 2)
The above can be split into:
num % 2 and + 10 * PrintInBinary(num / 2)
Assume num is 35.
num % 2 = 1
10 * PrintInBinary(num / 2) => 10 * PrintInBinary(17)
17 will be passed to the function (recursively).
This process will continue until num is 0
