Question

4. Write the linear equation whose graph contains the points (-2,5) and (4,1).

Answer 1

Thee linear equation which contains the points (-2,5) and (4,1) is $4x+6y-22=0$

Graph The points which is in the equation (-2,5) and (4,1).

Equation is basically a relationship between two or more variables and it is usually in equal to form. It is equated to find the value of variables. We can also make graphs of different equations. Linear equation is a equation whose graph looks like straight line means values comes from a relationship. It not necessarily means parallel to any axis.

The linear equation can be found by:

$(y-y_{1} )=(y_{2} -y_{1} )/(x_{2} -x_{1} )* (x-x_{1} )$ where the coordinates are $(x_{1},y_{1}), (x_{2},y_{2})$

$(y-5)=(1-5)/(4+2)*(x+2)$

$(y-5)=-4/6 *(x+2)$

$6y-30=-4x-8$

$y=(22-4x)/6$

Hence the equation which has points (-2,5)(4,1) is $4x+6y-22=0$

Learn more about equation at  brainly.com/question/2972832

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