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2 years ago

Need held ASAP I’m doing Ixl and I’m going to be posting a lot HELP HELP HELP HELP HELP HELP HELP

Mathematics

1 answer:

coldgirl [10]2 years ago

5 0

Answer:

28.27 square meters

Step-by-step explanation:

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ΔRST ≅ ΔXYZ. If RS = 13, YZ = 11, and XZ = 9, what is XY? A. 13 B. 9 C. 2 D. 11

Usimov [2.4K]

The answer is option "A, 13".

As both triangles are similar.
ΔRST ≅ ΔXYZ.
it means RS = XY
YZ = ST
and XZ = RT
Now given that RS = 13 which is equal to XY.
Thus XY is equal to 13.

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3 years ago

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A TV station wants to conduct a survey to determine which sport should be shown on Sunday in the viewing area: a football game o

love history [14]

Answer:

I'm not completely sure about this. The answer is B.) Sample 2: 50 boys and 50 girls at the local middle school. :)

Step-by-step explanation:

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3 years ago

Please help! Solve the inequality for x 3(x + 4) > 4 - X

Maurinko [17]

Answer:

x>-2

Step-by-step explanation:

3(x + 4) > 4 - X

Distribute

3x+12> 4-x

Add x to each side

3x+12+x > 4-x+x

4x+12 > 4

Subtract 12 from each side

4x+12-12>4-12

4x> -8

Divide each side by 4

4x/4 > -8/4

x>-2

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2 years ago

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What is the solution for f(n)=1.25n+6.25; 25??? Please answer this quickly

gogolik [260]

It would be f= 1.25n+6.25/n

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3 years ago

Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.

SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at $(0,1)$ .

The graph has an x-intercept at $(-7,0)$ .

Step-by-step explanation:

Given: The graph is $y=\sqrt[3]{x-1}+2$

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of $(-\infty, \infty)$ .

To find the y-intercept: To find the y-intercept, substitute $x=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}$

Thus, the y-intercept is $(0,1)$

To find the x-intercept: To find the x-intercept, substitute $y=0$ in $y=\sqrt[3]{x-1}+2$ .

$\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}$

Thus, the x-intercept is $(-7,0)$

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2 years ago

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