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2 years ago

I need answer as fast as possible please.

Mathematics

1 answer:

earnstyle [38]2 years ago

6 0

Step-by-step explanation:

a=110. x,55

y=180-(x+75)=50

w,75

b,110

x,40

y,30

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Questions<br> E<br> Given EA = 8 and AT = 10<br> Find ET

xxTIMURxx [149]

Answer:

ET = 80/A^2

Step-by-step explanation:

First, isolate the variables that you need, which is E and T, using the two equations you were given.

EA = 8

E = 8/A (divide A on both sides to isolate E)

AT = 10

T = 10/A (divide A on both sides to isolate T)

Now, substitute.

ET --> (8/A) x (10/A) = 80/A^2

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3 years ago

Maliha thinks of a number x write an expression for the number Maliha gets when she multiples the number by 3

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Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

In its monthly report, the local animal shelter states that it currently has 24 dogs and 18 cats available for adoption. Eight o

andrezito [222]

Answer with Step-by-step explanation:

We are given that

Total dogs=24

Total cats=18

Total animals=24+18=42

Male dogs=8

Male cats=6

Total male animals=8+6=14

Total female animals=42-14=28

Female cats=18-6=12

Dogs female=24-8=16

a.We have to find the probability that the pet is male, given that it is cat.

It means we have to find P(Male/cat)

Conditional probability: $P(A/B)=\frac{P(A\cap B)}{P(B)}$

P(Cat)= $\frac{18}{42}$

$P(male cat)=\frac{6}{42}$

$P(Male/cat)=\frac{\frac{6}{42}}{\frac{18}{42}}$

P(male/cat)= $\frac{6}{18}=0.33$

b. $P(female cat)=\frac{12}{42}$

$P(female)=\frac{28}{42}$

$P(Cat/Female)=\frac{\frac{12}{42}}{\frac{28}{42}}=\frac{12}{28}=0.43$

c.P(Dog)= $\frac{24}{42}$

$P(dog female)=\frac{16}{42}$

$P(female/dog)=\frac{\frac{16}{42}}{\frac{24}{42}}$

$P(female/dog)=\frac{16}{24}=0.67$

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3 years ago

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pav-90 [236]

d) x=-12 because x/-3=4 can be rearranged as x=4x-3 so x=-12

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3 years ago

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nevsk [136]

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https://www.ringgold.org/cms/lib/PA01916235/Centricity/Domain/227/Algebra%20I%20Keystone%20Review%20Packet%20Answer%20Key.pdf

there you go just a copy and a paste

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3 years ago

I need answer as fast as possible please.​

I need answer as fast as possible please.