Question

Calculate the area of triangle ABC with altitude CD, given A (6,0) B(1,5) C (2,0) and D (4,2)

Answer 1

So hmm check the picture below

the height or altitude is CD
and the base is AB

how long are those? well $\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ 6}}\quad ,&{{ 0}})\quad % (c,d) B&({{ 1}}\quad ,&{{ 5}})\\\\ C&({{ 2}}\quad ,&{{ 0}})\quad % (c,d) D&({{ 4}}\quad ,&{{ 2}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ AB=\sqrt{(1-6)^2+(5-0)^2}\qquad \qquad CD=\sqrt{(4-2)^2+(2-0)^2}$

Answer 2

Answer:

10 square units

Step-by-step explanation:

add the distances and round