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DerKrebs [107]
4 years ago
14

Calculate the area of triangle ABC with altitude CD, given A (6,0) B(1,5) C (2,0) and D (4,2)

Mathematics
2 answers:
Elina [12.6K]4 years ago
7 0
So hmm check the picture below

the height or altitude is CD
and the base is AB

how long are those? well \bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ 6}}\quad ,&{{ 0}})\quad 
%  (c,d)
B&({{ 1}}\quad ,&{{ 5}})\\\\
C&({{ 2}}\quad ,&{{ 0}})\quad 
%  (c,d)
D&({{ 4}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
AB=\sqrt{(1-6)^2+(5-0)^2}\qquad \qquad CD=\sqrt{(4-2)^2+(2-0)^2}

kirill115 [55]4 years ago
3 0

Answer:

10 square units

Step-by-step explanation:

add the distances and round

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Sladkaya [172]
Deposit = $1900
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% interest = 4%
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Time For Interest Period 

4/100 × 1900 × t = 1975.79
  76 t  = 1975.79
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Answer = 26years
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4) A 60 kg astronaut pushes against a 120 kg satellite with a force of 15 N. How much force does the satellite exert on the astr
Mkey [24]

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30n

Step-by-step explanation:

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3 years ago
The AARP (American Association of Retired People) report that at least 60% of retired people under the age of 65 would return to
mart [117]

Answer:

Step-by-step explanation:

Proportion of retired people under the age of 65 would return to work on a full-time basis if a suitable job were available = 60/100 = 0.6 = P

Null hypothesis: P ≤ 0.6

Alternative: P > 0.6

First, to calculate the hypothesis test, lets workout the standard deviation

SD =  √[ P x ( 1 - P ) / n ]

where P = 0.6, 1 - P = 0.4, n = 500

SD = √[ (0.6 x 0.4) / 500]

SD = √ (0.24 / 500)

SD = √0.00048

SD = 0.022

To calculate for the test statistic, we have:

z = (p - P) / σ where p = 315/500 = 0.63, P = 0.6, σ = 0.022

z = (0.63 - 0.6) / 0.022

z = 0.03/0.022

z = 1.36

At the 2% level of significance, the p value is less than 98% confidence level, thus we reject the null hypothesis  and conclude that more than 60% would return to work.

4 0
3 years ago
A business uses straight-line depreciation to determine the value y of an automobile over a 5-year period. Suppose the original
Elena-2011 [213]

For this problem. it is found that:

a) The automobile has depreciated 75% in 5 years.

b) The value of the automobile was reduced by $10,500 in five years.

c) The linear function is: s(t) = 14,500 - 2,100t.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = ax + b

In which:

  • a is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

From the problem, we have that:

a) The automobile has depreciated 75% in 5 years, as 4000/14500 = 0.25, and 100% - 25% = 75%.

b) The value of the automobile was reduced by $10,500 in five years, as 14500 - 4000 = $10,500.

For the linear function, we have that:

  • The initial value is b = 14500.
  • The slope is of a = -10500/5 = -2100.

Hence the linear function is: s(t) = 14,500 - 2,100t.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

6 0
2 years ago
Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (5,-12) lies o
svet-max [94.6K]

Answer:

Using A^2+B^2=C^2

12^2+5^2=169

Hypotenuse= 13

Sin(Ø)= 5/13

Cos(Ø)= 12/13

Tan(Ø)= 5/12

csc(Ø)=13/5

sec(Ø)=13/12

cot(Ø)=12/5

Please said thanks

8 0
4 years ago
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