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Novay_Z [31]
2 years ago
13

1.

Mathematics
1 answer:
Nataly [62]2 years ago
6 0
If the weight of the bottom box is b then the weight of a stack of four boxes is b + b/2 + b/4 + b/8
= 8b/8 + 4b/8 + 2b/8 + 1b/8
= 15/8 b
A stack must weigh less than 100 pounds
15/8 b < 100
b < 100 x 8/15 = 53 1/3 pounds
If boxes have a minimum weight of 1 pound then
for stacks that contain 4 boxes the range of b is [8, 53 1/3)
and if stacks contain 1 to 4 boxes the range of b is [1, 53 1/3)

If the only restriction is a maximum of 100 then the range of b is [0, 53 1/3)
You might be interested in
Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(O) = 2.8 y(t) =( Preview
Karolina [17]

Answer:

y=\frac{4}{5}e^{t}-\frac{4}{5}e^{-\frac{2}{5}t}

Step-by-step explanation:

The given equation 5y'' + 3y' - 2y =0 can be written as

(5D^{2}+3D-2)y(t)=0

Solving for complementary function we have Roots of (5D^{2}+3D-2) as follows

(5D^{2}+5D-2D-2)

5D(D+1)-2(D+1)=0\\\\(5D-2)(D+1)=0\\\\\therefore D=-1\\D=+2/5

Thus the complementary function becomes

y=y=c_{1}e^{m_{1}t}+c_{2}e^{m_{2}t}

where

m_{1},m_{2} are calculated roots

thus solution becomes

y=c_{1}e^{-t}+c_{2}e^{\frac{2}{5}t}

Now to solve for the coefficients we use the given boundary conditions

y(0)=0\\\\\therefore c_{1}+c_{2}=0\\\\y'(0)=-c_{1}+\frac{2}{5}c_{2}=2.8\\\\\therefore c_{2}+\frac{2}{5}c_{2}=2.8\\\\c_{2}=2\\\\\therefore c_{1}=-2}

hence the solution becomes

y=-2e^-{t}+2e^{\frac{2}{5}t}

8 0
3 years ago
Round 105.7 to the nearest whole number​
Nady [450]

Answer:

106

Step-by-step explanation:

When the decimal is 5 or greater, we round up. When the decimal is less than 5, we round down. For example, 105.4 would be rounded down to 105 because 4<5

Hope this helped!

4 0
3 years ago
Read 2 more answers
Find the area of shaded region
Anastaziya [24]

Answer: 107 units.

Step-by-step explanation: To find the area of the first box, you multiply the side lengths, which in this case are 5 by 7 to get 35. Then you find the area of the second box by multiplying 8 * 10 which is 80 so the total area of everything is 115 units. Then you subtract the non - shaded region which is 2 * 4 units. So after subtracting 115 - 8, you get your final answer of 107 units.

4 0
3 years ago
Read 2 more answers
Please help! Its for my big test tomorrow!
Travka [436]

Answer:

# The solution x = -5

# The solution is x = 1

# The solution is x = 6.4

# The solution is x = 4

# The solution is 1.7427

# The solution is 0.190757

Step-by-step explanation:

* Lets revise some rules of the exponents and the logarithmic equation

# Exponent rules:

1- b^m  ×  b^n  =  b^(m + n) ⇒ in multiplication if they have same base

  we add  the power

2- b^m  ÷  b^n =  b^(m – n) ⇒  in division if they have same base we

   subtract  the power

3- (b^m)^n = b^(mn) ⇒ if we have power over power we multiply

   them

4- a^m × b^m = (ab)^m ⇒ if we multiply different bases with same  

   power then we multiply them ad put over the answer the power

5- b^(-m) = 1/(b^m)  (for all nonzero real numbers b) ⇒ If we have

   negative power we reciprocal the base to get positive power

6- If  a^m  =  a^n  ,  then  m  =  n ⇒ equal bases get equal powers

7- If  a^m  =  b^m  ,  then  a  =  b    or    m  =  0

# Logarithmic rules:

1- log_{a}b=n-----a^{n}=b

2- loga_{1}=0---log_{a}a=1---ln(e)=1

3- log_{a}q+log_{a}p=log_{a}qp

4- log_{a}q-log_{a}p=log_{a}\frac{q}{p}

5- log_{a}q^{n}=nlog_{a}q

* Now lets solve the problems

# 3^{x+1}=9^{x+3}

- Change the base 9 to 3²

∴ 9^{x+3}=3^{2(x+3)}=3^{2x+6}

∴ 3^{x+1}=3^{2x+6}

- Same bases have equal powers

∴ x + 1 = 2x + 6 ⇒ subtract x and 6 from both sides

∴ 1 - 6 = 2x - x

∴ -5 = x

* The solution x = -5

# ㏒(9x - 2) = ㏒(4x + 3)

- If ㏒(a) = ㏒(b), then a = b

∴ 9x - 2 = 4x + 3 ⇒ subtract 4x from both sides and add 2 to both sides

∴ 5x = 5 ⇒ divide both sides by 5

∴ x = 1

* The solution is x = 1

# log_{6}(5x+4)=2

- Use the 1st rule in the logarithmic equation

∴ 6² = 5x + 4

∴ 36 = 5x + 4 ⇒ subtract 4 from both sides

∴ 32 = 5x ⇒ divide both sides by 5

∴ 6.4 = x

* The solution is x = 6.4

# log_{2}x+log_{2}(x-3)=2

- Use the rule 3 in the logarithmic equation

∴ log_{2}x(x-3)=2

- Use the 1st rule in the logarithmic equation

∴ 2² = x(x - 3) ⇒ simplify

∴ 4 = x² - 3x ⇒ subtract 4 from both sides

∴ x² - 3x - 4 = 0 ⇒ factorize it into two brackets

∴ (x - 4)(x + 1) = 0 ⇒ equate each bract by 0

∴ x - 4 = 0 ⇒ add 4 to both sides

∴ x = 4

OR

∵ x + 1 = 0 ⇒ subtract 1 from both sides

∴ x = -1

- We will reject this answer because when we substitute the value

 of x in the given equation we will find log_{2}(-1) and this

 value is undefined, there is no logarithm for negative number

* The solution is x = 4

# log_{4}11.2=x

- You can use the calculator directly to find x

∴ x = 1.7427

* The solution is 1.7427

# 2e^{8x}=9.2 ⇒ divide the both sides by 2

∴ e^{8x}=4.6

- Insert ln for both sides

∴ lne^{8x}=ln(4.6)

- Use the rule ln(e^{n})=nln(e) ⇒ ln(e) = 1

∴ 8x = ln(4.6) ⇒ divide both sides by 8

∴ x = ln(4.6)/8 = 0.190757

* The solution is 0.190757

7 0
4 years ago
Read 2 more answers
Solve this question<br> 2(x+3)=x-4
Whitepunk [10]

Answer:

x=-10

Step-by-step explanation:

2(x+3)=x-4 (Multiply the 2 by the x and the 3);

2x+6=x-4 (Now you group like terms)

2x-x=-4-6

x=-10

8 0
3 years ago
Read 2 more answers
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