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Murljashka [212]
2 years ago
5

Someone please help me

Mathematics
1 answer:
zimovet [89]2 years ago
3 0

Answer:

1 infinity

2 one

3 no

4 one

5 infinity

Step-by-step explanation:

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Someone plz help because I am using my last amount of points and I don't want it to be wasted from no answer.I need help with qu
ser-zykov [4K]
Wheres the questions???
7 0
2 years ago
The graph of a function f is shown. Use the graph to estimate the average rate of change from x = –2 to x = 0
vodomira [7]

Answer:

Average rate of change = 2

Step-by-step explanation:

Formula to get the rate of change of a function between x = b and x = a is,

Rate of change = \frac{f(b)-f(a)}{b-a}

We have to calculate the average rate of change between x = -2 and x = 0

From the graph attached,

At x = -2,

f(-2) = 0

At x = 0,

f(0) = 4

Therefore, average rate of change = \frac{f(0)-f(-2)}{0-(-2)}

                                                          = \frac{4-0}{2}

                                                          = 2

Average rate of change of the given function between x = -2 and x = 0 is 2.

4 0
3 years ago
5.066rounded to the nearest hundredth
vladimir2022 [97]
If you round 5.066 to the nearest hundredth it would be 5.07 
5 0
3 years ago
Read 2 more answers
A 2-yard piece of ribbon costs $37.20. What is the price per foot?​
HACTEHA [7]

Answer:$6.20

Step-by-step explanation:

Divide 37.29 by 2

Then you find out how many feet is in a yard which is three so then divide again by 3...I misread

3 0
3 years ago
Read 2 more answers
A new, simple test has been developed to detect a particular type of cancer. The test must be evaluated before it is used. A med
g100num [7]

Answer:

0.3333 = 33.33% probability of a randomly chosen person not having cancer given that the test indicates cancer

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test indicates cancer.

Event B: Person does not have cancer.

Probability of a test indicating cancer.

98% of 2%(those who have).

1% of 100 - 2 = 98%(those who do not have). So

P(A) = 0.98*0.02 + 0.01*0.98 = 0.0294

Probability of a test indicating cancer and person not having.

1% of 98%. So

P(A \cap B) = 0.01*0.98 = 0.0098

What is the probability of a randomly chosen person not having cancer given that the test indicates cancer?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0098}{0.0294} = 0.3333

0.3333 = 33.33% probability of a randomly chosen person not having cancer given that the test indicates cancer

3 0
3 years ago
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