Answer:
a) 0.78 s
b) 58.86m/s'
c) Galileo's law of free fall
Explanation:
a)
b)At the bottom:
kinetic energy = potential energy
downwards
c) Galileo's law of free fall says regardless of the masses, bodies in a vacuum will fall, on the earth, at the same acceleration
Answer:
The anserrs to the question are
(a) The temperature would be 566.67 K and
(b) The pressure of the resulting air stream is 14 bar
Explanation:
Here the two streams of gases meet ad form a single stream
The steady-flow energy equation can be implemented at the mixing point of the to streams as follows
mₐhₐ₁ + mₙ hₙ₁ + Q° + W° = mₐhₐ₂ + mₙhₙ₂
Where the flow is adiabatic, we have
Q = 0 and W = 0 hence
mₐhₐ₁ + mₙ hₙ₁ = mₐhₐ₂ + mₙhₙ₂ where h = cp×T we have
mₐcpₐ×Tₐ + mₙcpₙ×Tₙ = mₐcpₐ×T + mₐcpₙ×T
Therefore the final temperature T is given by
for the same kind of gas cpₐ =cpₙ therefore
where mₐ and mₙ are mass flow rate
Therefore we have where Tₐ = = 900 K and Tₙ = 400 K and mₙ = 2mₐ gives
=
= 1700/3 = 566.67 K
From Dalton's law, the total pressure of a mixture of gases is equal to the sum of the partial pressures of the components of the mixture
Therefore the total pressure of the combined stream = pₐ + pₙ = p
= 12 bar + 2 bar = 14 bar
Stream pressure = 14 bar
Answer :
(a) The acceleration of the car is,
(b) The distance covered by the car is, 150 m
Explanation :
By the 1st equation of motion,
...........(1)
where,
v = final velocity = 5 m/s
u = initial velocity = 25 m/s
t = time = 10 s
a = acceleration of the car = ?
Now put all the given values in the above equation 1, we get:
The acceleration of the car is,
By the 2nd equation of motion,
...........(2)
where,
s = distance covered by the car = ?
u = initial velocity = 25 m/s
t = time = 10 s
a = acceleration of the car =
Now put all the given values in the above equation 2, we get:
By solving the term, we get:
The distance covered by the car is, 150 m
Radius of Earth is given as
now here the height from the surface of earth is same as that of radius
now here the acceleration due to gravity at this height is given as
now the force of gravity on the given object will be
<em>so the force of gravity on it is 1.225 N</em>