Given that the velocity of a car increases by 40 m/s in 80 seconds, the acceleration of the car will be given by:
a=(final velocity-initial velocity)/(time)
thus;
final velocity=40 m/s
initial velocity=0
time=80 seconds
hence;
a=(40-0)/80
=0.5m/s^2
Answer 41.7 years old
I answer this question already and it was correct!
Answer:
Yes, this is according to the Newton's first law of motion.
Neither its direction nor its velocity changes during this course of motion.
Explanation:
Yes, it is very well in accordance with Newton's first law of motion for a body with no force acting on it and it travels with a non-zero velocity.
During such a condition the object will have a constant velocity in a certain direction throughout its motion. Neither its direction nor its velocity changes during this course of motion.
Answer:
right after jumping so 0s and as it falls its speed will keep increasing
Explanation:
<h2>Greetings!</h2>
To find speed, you need to remember the formula:
Speed = distance ÷ time
So plug the given values in:
500 ÷ 30 = 16.66
<h3>So the speed is 16.66m/s (metres per second)</h3>
<h2>Hope this helps!</h2>
