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umka2103 [35]
3 years ago
11

Explain the change of frequency of the wave if the tension of the string is increased​

Physics
1 answer:
jek_recluse [69]3 years ago
8 0

Answer:

Increasing the tension on a string increases the speed of a wave, which increases the frequency (for a given length). Pressing the finger at different places changes the length of string, which changes the wavelength of standing wave, affecting the frequency.

Explanation:

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Three dogs (Spot, Fido, and Steinberg) are pulling on a chew toy. The chew toy is experiencing no acceleration. Spot is pulling
quester [9]

Answer:

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

Explanation:

The chew toy is at equilibrium and experimenting three forces from three distinct dogs. The Free Body Diagram depicting the system is attached below. By Newton's Laws we construct the following equations of equilibrium: (<em>Sp</em> is for Spot, <em>F</em> is for Fido and <em>St</em> is for Steinberg) All forces and angles are measured in newtons and sexagesimal degrees, respectively:

\Sigma F_{x} = F_{F}\cdot \cos \theta_{F} + F_{St,x} = 0 (1)

\Sigma F_{y} = F_{F}\cdot \sin \theta_{F}-F_{Sp}+F_{St,y} = 0 (2)

If we know that F_{F} = 20\,N, F_{Sp} = 30\,N and \theta_{F} = 63^{\circ}, then the components of the force done by Steinberg on the chewing toy is:

F_{St,x} = -F_{F}\cdot \cos \theta_{F}

F_{St,x} = -(20\,N)\cdot \cos 63^{\circ}

F_{St, x} = -9.080\,N

F_{St,y} = F_{Sp}-F_{F}\cdot \sin \theta_{F}

F_{St,y} = 30\,N-(20\,N)\cdot \sin 63^{\circ}

F_{St, y} = 12.180\,N

The magnitud of the force is determined by Pythagorean Theorem:

F_{St} = \sqrt{F_{St,x}^{2}+F_{St,y}^{2}}

F_{St} =\sqrt{(-9.080\,N)^{2}+(12.180\,N)^{2}}

F_{St} \approx 15.192\,N

Since the direction of this force is in the 3rd Quadrant on Cartesian plane, we determine the direction of the force with respect to the eastern semiaxis:

\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{F_{St,y}}{F_{St,x}}\right)

\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{12.180\,N}{-9.080\,N}\right)

\theta_{St} \approx 126.704^{\circ}

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

5 0
3 years ago
A 2 N and an 8 N force pull on an object to the right and a 4 N force pulls on the same object to the left. If the object has a
Elden [556K]

Answer:

a = 12 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

ΣF = sum of forces acting on a body [N] (units of Newtons)

m = mass = 0.5 [kg]

a = acceleration [m/s²]

Let's take the direction of positive forces to the right and negative forces directed to the left

2 + 8 - 4 = 0.5*a

6 = 0.5*a

a = 12 [m/s²]

7 0
3 years ago
Which statement is most likely correct?
Len [333]

it's either the first or second choice

6 0
3 years ago
Read 2 more answers
So, what is the answer of this assignment?
Ket [755]
What assignment, you have to work with me here i don't know what were working on
6 0
3 years ago
A motorboat maintained a constant speed of 15 miles per hour relative to the water in going 10 miles upstream and then returning
Lesechka [4]

Answer:

speed of current is 5 mile/hr

Explanation:

GIVEN DATA:

speed of motorboat = 15 miles/hr relative with water

let c is speed of current

15-c is speed of boat at  upstream

15+c is speed of boat at downstream

we know that

travel time=distance/speed

\frac{10}{15-c} +\frac{10}{15+c} = 1.5

150+10c+150-10c=1.5(15-c)(15+c)

300=1.5(225-c^2)

300=337.5-1.5c^2

200=225-c^2

c^2=25

c = 5

so speed of current is 5 mile/hr

6 0
3 years ago
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