Question

One of the two of A two digit is three times the other digit. if you interchange the digits of this two digit number and add the resulting number to the original number you get 88.what is the original number. give solution
ASAP PLEASE​

Answer 1

Given that, one digit of a two digit number is three times the other digit.

Let assume that digit at ones place be x.

digit at ones place be x.So, digit at tens place be 3x.

digit at ones place be x.So, digit at tens place be 3x.So, two digit original number = 10 × 3x + 1 × x = 30x + x = 31x

Now, number formed on interchanging its digits, i.e.

Reverse number = 10 × x + 1 × 3x = 10x + 3x = 13x

According to statement, if we interchange the digits of this two digit number and add the resulting number to the original number, we get 88.

$\begin{gathered}\sf \: 31x + 13x = 88 \\ \\ \end{gathered}$

$\begin{gathered}\sf \: 44x = 88 \\ \\ \end{gathered}$

$\begin{gathered}\sf \: x = \dfrac{88}{44} \\ \\ \end{gathered}$

$\begin{gathered}\sf\implies \: x = 2 \\ \\ \end{gathered}$

So, two digit number is 31 × 2 = 62

Hence,

$\begin{gathered}\sf\implies \: \boxed{ \bf{ \:Original \: number \: = \: 62 \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

Answer 2

Answer:

26 or 62

Step-by-step explanation:

If one of the two digits of a two-digit number is three times the other digit, then the options for the two-digit number are:

• 13 or 31
• 26 or 62
• 39 or 93

If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88.

From inspection of the listed pairs of numbers, the only pair that sums to 88 is 26 and 62:

⇒ 26 + 62 = 88

Therefore, the original number is either 26 or 62.