You can just look up "python ide online" on google and paste this code:
n = -1
count = 0
while n < 0:
n = int(input("We're checking to see if a number is prime or not! Enter a positive number: "))
if n % 2 == 0:
if n == 2:
print("{} is a prime number".format(n))
else:
print("{} is not a prime number".format(n))
else:
for x in range(n, 1, -1):
if n % x == 0:
count += 1
if count > 1 or n == 1:
print("{} is not a prime number".format(n))
else:
print("{} is a prime number".format(n))
I've written some code that checks to see if a number entered by the user is a prime number or not.
Sorry, but I'm not too good with pseudocode plans and all that. I hope this helps.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
First, we need to convert these hexadecimal numbers into decimal numbers, then we can easily identify which one is the lowest hexadecimal.
The hexadecimal numbers are F2, 81, 3C, and 39.
F2 = (F2)₁₆ = (15 × 16¹) + (2 × 16⁰) = (242)₁₀
81 = (81)₁₆ = (8 × 16¹) + (1 × 16⁰) = (129)₁₀
3C = (3C)₁₆ = (3 × 16¹) + (12 × 16⁰) = (60)₁₀
39 = (39)₁₆ = (3 × 16¹) + (9 × 16⁰) = (57)₁₀
The 39 is the lowest hexadecimal number among the given numbers.
Because 39 hex is equal to 57 decimal.
39 = (39)₁₆ = (3 × 16¹) + (9 × 16⁰) = (57)₁₀
A pallet jack is a manually operated forklift
It would be the last one, because she isn't recording any type of data over what she is doing and she isn't observing it at all. She simply trimmed the stems of a bouquet of flowers. However, the other options insist that they are recording data and observing, like you would do when performing an experiment. I hope this helps! :)
Answer:
That's because the value has reached the size limit of the int data type. ... you should use long rather than int , because long can store much larger numbers than int . If ... In other words, a float or double variable can't accurately represent 0.1 . ... If you're using Java to measure the size of your house, you'd need an electron ...
Explanation:
