Answer:
I feel like it b hope it correct though
Answer:
45%
Step-by-step explanation:
PLEASE MARK ME AS BRAINLIEST I REALLY WANT TO LEVEL UP
Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.The expressions which are equivalent to the given expression are,
Given information-
The expression given in the problem is,

<h3>Equivalent expression-</h3>
Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.
For given expression,

As the above function is the function of <em>x. </em>Thus it can be written as,

<h3>Logarithm power rule</h3>
Logarithm power rule states that the exponent of the logarithm function can transfers to front of the logarithm and vice versa. Thus,

Now the value of
is equal to the zero. Thus,

Hence the expressions which are equivalent to the given expression are,
Learn more about the equivalent expression here;
brainly.com/question/10628562
Answer:
a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4
Step-by-step explanation:
for the equation
(1 + x⁴) dy + x*(1 + 4y²) dx = 0
(1 + x⁴) dy = - x*(1 + 4y²) dx
[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx
∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx
now to solve each integral
I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁
I₂= ∫[-x/(1 + x⁴)] dx
for u= x² → du=x*dx
I₂= ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ = - tan⁻¹ (x²) +C₂
then
1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C
for y(x=1) = 0
1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C
since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for π*N , we will choose for simplicity N=0 . hen an explicit solution would be
1/2 * 0 = - π/4 + C
C= π/4
therefore
1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4
Answer:
(8, -8)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = x - 16
5y = 2x - 56
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in <em>y</em>: 5(x - 16) = 2x - 56
- Distribute 5: 5x - 80 = 2x - 56
- [Subtraction Property of Equality] Subtract 2x on both sides: 3x - 80 = -56
- [Addition Property of Equality] Add 80 on both sides: 3x = 24
- [Division Property of Equality] Divide 3 on both sides: x = 8
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x - 16
- Substitute in <em>x</em>: y = 8 - 16
- Subtract: y = -8