Question

A sample of gas has temperature of 372 K and pressure of 3.8 ATM. If the temperature is increased to 550 K, what is the new pressure?

Answer 1

Answer: The correct answer is 5.6atm.

Explanation: Since we only have information on the pressure and temperature, we will use Gay-Lussac's Law: $\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }$. Now that we have the formula, let's plug in our given information!

$\frac{3.8atm}{372K} =\frac{P_{2} }{550K}$

We must find the value $P_{2}$. To do this, we will write a stoichiometric equation to solve this.

$P_{2} =\frac{3.8atm*550K}{372K}$

Let's input the numbers into a scientific calculator to get our answer!

$P_{2} =\frac{3.8atm*550K}{372K}=5.6 atm$

Given all of this work, the value $P_{2}$ equals 5.6 atm.

I hope this helps! Pls give brainliest!! :)