I'm assuming you meant 10^(14) instead of 1014
if so, then the energy of one photon will be be 4.76×10^(-19) Joules
2AgBr+Cl2=2AgCl+Br2
You want everything to be the same on both sides the easiest way to do that is draw a line down the equal sign and write out all you compound and how many there are and do the same on the other side until there even
Unit of M is also mole/L, where mole is the moles of solute and L is the volume of the solution. The latter is given: 158 mL or 0.158 L. So we need to find out the moles of NH4Br.
Moles of NH4Br = Mass of NH4Br/molar mass of NH4Br = 17.0g/(14+1*4+79.9)g/mol = 0.1736 mole.
So, the molarity of the solution = 0.1736mole/0.158L = 1.10 mole/L = 1.10 M
Answer:THIS IS NOT THE ANSWER
is this for the chemistry A final 10th grade for connexus (unit7 lesson 2)?
Explanation:
The balanced equation for the above neutralisation reaction is as follows;
2KOH + H₂SO₄ --> K₂SO₄ + 2H₂O
stoichiometry of KOH to H₂SO₄ is 2:1
neutralisation is the reaction between H⁺ ions and OH⁻ ions to form water which is neutral
number of KOH moles - 1.56 mol
2 mol of KOH require 1 mol of H₂SO₄ for neutralisation
therefore 1.56 mol of KOH require - 1/2 x 1.56 mol = 0.78 mol
0.78 mol of H₂SO₄ are required for neutralisation
