Answer:
Fractional distillation
Explanation:
Crude oil, also known as petroleum, is a naturally occurring substance found in the Earth's crust. It is a mixture of different useful substances. These substances are separated from one another based on their individual boiling points in a process called FRACTIONAL DISTILLATION.
The process of fractional distillation entails the application of heat to the crude oil. The different fractions evaporate and condense in the fractionating column depending on their boiling point. The hydrocarbon substances separated are called fractions, and they include bitumen, diesel, kerosene, gasoline, natural gas etc. Therefore, before we can use gasoline (petrol) in our cars, the crude oil needs to be separated into separate products like plastics and ink. This process is called FRACTIONAL DISTILLATION.
Answer:
KMnO4,H3O^+,75°C
Explanation:
The conversion of cyclohexene to trans-1,2-cylohexanediol is an oxidation reaction. Alkenes are oxidized in the presence of potassium permanganate and acids to yield the corresponding diols.
These diols may also be called glycols. They are molecules that contain two -OH(hydroxyl) groups per molecule. The reaction closely resembles the addition of the two -OH groups of hydrogen peroxide to an alkene.
The bright color of potassium permanganate disappears in this reaction so it can be used as a test for alkenes.
Electronic Configuration of Cu⁴⁺ is written using these two steps;
Step I:
Write the Electronic Configuration of Copper (Cu).
As Atomic Number of Cu = 29
So,
1s², 2s², 2p⁶, 3s², 3p⁶, 3d¹⁰, 4s¹
Rearranging it in order of increasing orbital energy,
1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹, 3d¹⁰
Or,
Cu = [Ar] 4s¹, 3d¹⁰
Step II:
Now, the Cu⁴⁺ ion has lost 4 electrons, So one electron from 4s and 3 electrons from 3d orbital are removed, The resulting electronic configuration becomes,
Cu⁴⁺ = [Ar] 3d⁷
<h3>Answer:</h3>
Molecular Formula = S₂O₂ (Disulfur Dioxide)
<h3>Solution:</h3>
Molecular formula is calculated by using following formula,
Molecular Formula = n × Empirical Formula ---- (1)
Also, n is given as,
n = Molecular Weight / Empirical Formula Weight
Molecular Weight = 96.13 g.mol⁻¹
Empirical Formula Weight = 32.06 (S) + 16.0 (O) = 48.06 g.mol⁻¹
So,
n = 96.13 g.mol⁻¹ ÷ 48.06 g.mol⁻¹
n = 2.0002 ≈ 2
Putting Empirical Formula and value of "n" in equation 1,
Molecular Formula = 2 × SO
Molecular Formula = S₂O₂ (Disulfur Dioxide)
