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3 years ago

A barium atom attains a stable electron configuration when it bonds with?

Chemistry

1 answer:

adell [148]3 years ago

6 0

The answer is B. two chlorine atoms.
The chemical formula of the compound is BaCl2~

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An empty steel container is filled with 2.0 atm of H₂ and 1.0 atm of F₂. The system is allowed to reach equilibrium according to

Darina [25.2K]

H₂ (g) + F₂ (g) ⇌ 2 HF (g)

5 0

3 years ago

The weak acid HZ has a Ka of 2.55x10⁻⁴.(a) Calculate the pH of 0.075 M HZ.

Dima020 [189]

<u>2.37</u> is the pH of 0.075 M HZ.

The term pH, which originally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are summarized for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions.

The pH scale is inversely indicates to the concentration of hydrogen ions in the solution and is logarithmic.

⇒pH = -log( $a_{H+}$ )

Acidic solutions are those with a pH below 7, and basic solutions are those with a pH above 7, at a temperature of 25 °C (77 °F). At this temperature, solutions with a pH of 7 are neutral (e.g. pure water). The pH neutrality relies on temperature, falling below 7 if the temperature rises above 25 °C.

Learn more about pH

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#SPJ4

4 0

2 years ago

Na podstawie położenia w u.o. oraz liczb A i Z:

Dvinal [7]

Ok A is the correct answer

5 0

3 years ago

Read 2 more answers

If a lab requires each lab group to have 25ml of a solution and it takes 15 grams of CuNO3 to make 1 liter of solution how many

tino4ka555 [31]

We need to do some general algebra here.

We will find that you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.

Each lab group needs 25 ml of solution.
it takes 15 g of CuNO₃ to make one L of that solution.
There are 22 labs.

Because each lab needs 25 ml of solution, 22 labs will need that amount 22 times, so the <u>total amount of solution needed</u> is:

22*25ml = 550 ml

Now we know that we need 15 grams to make one liter of solution, and:

1 L = 1000ml

Then you need 15g to make 1000ml

and x (we want to find this amount) to make 550ml

Then we can write two equations (not actual equations, as these are different units) like:

x = 550ml

15g = 1000ml

Now we can take the quotient between these two equations:

x/15 g = (550ml/1000ml)

And now we can solve this for x:

x = (550ml/1000ml)*15g = 8.25g

So you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.

If you want to learn more, you can read:

brainly.com/question/8743486

5 0

3 years ago

8.7g+15.43g+19g?<br> 853.2L-627.443L?<br> 5.47m+11m+87.300m?

gizmo_the_mogwai [7]

the god ran down the street

6 0

3 years ago