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Sphinxa [80]
3 years ago
9

184500 $ are to be divided between 2 people. One person has 80% of what the other person has. How much does each one receive in

$?​
Mathematics
1 answer:
Annette [7]3 years ago
6 0

Given:

$184500 are to be divided between 2 people.

One person has 80% of what the other person has.

To find:

The amount each one receive in $.

Solution:

Let $x be the amount received by first person. Then,

Amount received by the second person = 80% of x

                                                                   = 0.80x

Total amount = Amount received by first person + by second person

                      =x+0.80x

                      =1.80x

Total amount is 184500. So,

1.80x=184500

x=\dfrac{184500}{1.80}

x=102500

So, the amount received by the first person is $102,500.

0.80x=0.80\times 102500

0.80x=82000

So, the amount received by the second person is $82,000.

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Answer:

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(b) The probability of getting the correct combination in the first try is \frac{1}{216000}.

Step-by-step explanation:

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The numbers can be repeated.

(a)

There are three cylinder combinations on the lock, each with 60 numbers.

It is provided that repetitions are allowed.

Then each cylinder can take any of the 60 numbers.

So there are 60 options for the first cylinder.

There are 60 options for the second cylinder.

And there are 60 options for the third cylinder.

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Thus, the number of different lock combinations is 216,000.

(b)

The events of getting a correct combinations of the three​-cylinder combination lock implies that all the three cylinder are set at the correct numbers.

Each cylinder has 60 numbers.

This implies that there are 60 possible ways to get a correct number for the first cylinder.

The probability of getting the correct number for the first cylinder is:

P (Number on 1st cylinder is correct) = \frac{1}{60}.

Similarly for the second cylinder the probability of getting the correct number is:

P (Number on 2nd cylinder is correct) = \frac{1}{60}.

And similarly for the third cylinder the probability of getting the correct number is:

P (Number on 3rd cylinder is correct) = \frac{1}{60}.

So the probability of getting the correct combination in the first try is:

P (Correct combination in the 1st try) = \frac{1}{60}\times \frac{1}{60}\times \frac{1}{60}=\frac{1}{216000}.

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ad-work [718]

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Given:

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