Answer:
function pecoDesconto(preco, estaComDesconto) {
let p = preco;
let desconto = estaComDesconto;
if(p > 100 && desconto == false){
return "Quero pechinchar";
}else{
return "Negócio fechado";
}
}
Explanation:
function pecoDesconto(preco, estaComDesconto) {
// Implemente a função ao lado, que recebe um preço//
let p = preco;
// variavel que indica desconco//
let desconto = estaComDesconto;
//Se o preço for maior que 100 e não estiver com desconto, a função deve retornar Quero pechinchar.//
if(p > 100 && desconto == false){
return "Quero pechinchar";
//Caso contrário, deve retornar Negócio fechado
}else{
return "Negócio fechado"
}
}
só te faltou ler com atenção, e um pouco de logica!
False.
The different between break and continue instruction is that with break you exit the loop, and with continue you skip to the next iteration.
So, for example, a loop like
for(i = 1; i <= 10; i++){
if(i <= 5){
print(i);
} else {
break;
}
}
will print 1,2,3,4,5, because when i=6 you will enter the else branch and you will exit the loop because of the break instruction.
On the other hand, a loop like
for(i = 1; i <= 10; i++){
if(i % 2 == 0){
print(i);
} else {
continue;
}
}
Will print 2,4,6,8,10, because if i is even you print it, and if i is odd you will simply skip to the next iteration.
Answer:
Mouse and Keyboard are the devices which can be used to give input to the computer.
Explanation:
Mouse and Keyboard both are connected with the CPU via USB cable. Mouse consists of 3 major buttons, left button(for click to get the task to be done), right button (to get options) and wheel (to scroll up and down the page on screen). Keyboard is use to type text and letters as per need.
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
